Total number of stereoisomers possible for the followingcompounds isHINT:a. 4How many possible stereoisomers?How do we know how many stereoisomers are possible for a given structure? There is actually a straightforward way to figure this out. All we need to do iscount the number of chiral centers and stereogenic alkene groups, the use this following rule:number of stereoisomeric forms = 2"... where n = the number of chiral centers plus the number of stereogenic alkene groupsb. 2Consider for example a molecule with two chiral centers and one stereogenic alkene. By the rule stated above, we know right away that there must be eightpossible stereoisomers.terminal alkeneOHstereogenic alkeneC. 8OHd. 3OHchiral centerHOOH32 = 8Tnonstereogenic alkenes (cannot be labelled E or Z)←

Number of stereo isomer depends on number of chiral centre. The formula given here is 2n = number of…

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Total number of stereoisomers possible for the following compounds is HINT: OH OH HO How many possible stereoisomers?

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter6: Alkanes & Alkenes

Section: Chapter Questions

Problem 4E: Consider the molecule 1-bromo-2-methylbutane. C3 and C4 should be drawn as Et as in theexample. This...

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Concept explainers

Alkanes and Cycloalkanes

Alkanes are saturated organic compounds which are made up of C and H atoms. Alkanes have the general formula of CnH2n+2. Alkane contains sp3 hybridized carbon atoms with four sigmas (σ) bonds & every hydrogen atom is connected with one of the carbon atoms. The size of the alkane could be determined by the number of carbon atoms located in it.

Question

Total number of stereoisomers possible for the following
compounds is
HINT:
a. 4
How many possible stereoisomers?
How do we know how many stereoisomers are possible for a given structure? There is actually a straightforward way to figure this out. All we need to do is
count the number of chiral centers and stereogenic alkene groups, the use this following rule:
number of stereoisomeric forms = 2"
... where n = the number of chiral centers plus the number of stereogenic alkene groups
b. 2
Consider for example a molecule with two chiral centers and one stereogenic alkene. By the rule stated above, we know right away that there must be eight
possible stereoisomers.
terminal alkene
OH
stereogenic alkene
C. 8
OH
d. 3
OH
chiral center
HO
OH
3
2 = 8
T
nonstereogenic alkenes (cannot be labelled E or Z)
←

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