
Cheerleaders standing and moving in the shape of a sinusoidal
At first, the sine curve increases at the far left of the field. The amplitude is 80 ft and the period is 60 ft. What is the sine ccurv's equation? (Is it y = 80 sin(π/30x + 5π) + 80?)
The cheerleaders move and the curve becomes half as tall as it was before. (I assume that I would just have to divide the amplitude by 2? 80 becomes 40?)
The cheerleaders move again so tht the sine curve is in the lower half of the stadium. What is the equation? (I believe that in the equation y = A sin(Bx + C) + D, D was 80, but because they are in the lower half of the stadium, D becomes 40?)
The cheerleaders move the entire sine curve to off the stadium to the right, the first cheerleader forming the curve stands at the 5 year line. What would the equation be?

Trending nowThis is a popular solution!
Step by stepSolved in 2 steps

- Trigonometry (11th Edition)TrigonometryISBN:9780134217437Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie DanielsPublisher:PEARSONTrigonometry (MindTap Course List)TrigonometryISBN:9781305652224Author:Charles P. McKeague, Mark D. TurnerPublisher:Cengage Learning
- Trigonometry (MindTap Course List)TrigonometryISBN:9781337278461Author:Ron LarsonPublisher:Cengage Learning



