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- Wolff-Kishner reduction of compound W gave compound A. Treatment of A with m-chloroperbenzoic acid gave B which on reduction with LiAH4 gave C. Oxidation of compound C with chromic acid gave D (C9H14O). Suggest the structures for A, B, C, and D.Two isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H2O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. Which of the following isomeric pairs best match this data?Two isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H2O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. What is the isometric pair of A and B that corresponds?
- 16. When cis-1,2-cyclopentanediol reacts with acetone in dry HCl, compound M is formed. What do you expect the hydrolysis of compound M to be when subjected (i) to base; and, (ii) acid a. resistant to base; resistant to acid b. resistant to base; readily hydrolyzed by acid c. readily hydrolyzed by base; resistant to acid d. readily hydrolyzed by base; readily hydorlyzed by acid 17. Following (16), would you expect that a similar compound be formed if the reactant was trans-1,2-cyclopentanediol? Why is this so? a. Yes; hydroxyl groups are on opposite side b. No; hydroxyl groups are on opposite site c. Yes; hydroxyl groups are on the same side d. No; hydroxyl groups are on the same sideCompound J, C16H16Br2, is optically active. On treatment with strong base, compounds K and L (each C16H14) are formed; K and L each absorb only 2 equivalents of hydrogen when reduced over a Pd/C catalyst. Compound K reacts with ozone to give phenylacetic acid (C6H5CH2COOH), while similar treatment of L gives 2 products. One product, M, is an aldehyde with formula C7H6O; the other product is glyoxal (CHO)2. Draw the structure of compound L.Compound X is optically inactive and has the formula C 16H 16Br 2. On treatment with strong base, X gives hydrocarbon Y, C 16H 14. Compound Y absorbs 2 equivalents of hydrogen when reduced over a palladium catalyst and reacts with ozone to give two fragments. One fragment Z, is an aldehyde with formula C 7H 6O. The other fragment is glyoxal, (CHO)2. Which of the following answers is correct? Select all that are correct.
- Provide a stepwise synthesis for benzyl chloride to benzyl alcohol with reagents Na2CO3 and H2O.(including arrow-pushing mechanisms) Please show all the arrow push(a) Arrange the following compounds in an increasing order of their indicated property :(i) Benzoic acid, 4-Nitrobenzoic acid, 3,4-Dinitrobenzoic acid, 4-Methoxybenzoic acid (acid strength)(ii) CH3CH2CH (Br) COOH, CH3CH (Br) CH2COOH,(CH3)2CHCOOH, CH3CH2CH2COOH (acid strength)(b) How would you bring about the following conversions :(i) Propanone to Propene (ii) Benzoic acid to Benzaldehyde(iii) Bromobenzene to 1-phenylethanolAcid-catalyzed hydrolysis of HOCH2CH2C(CH3)2CN forms compound A (C6H10O2). A shows a strong peak in its IR spectrum at 1770 cm-1 and the following signals in its 1H NMR spectrum: 1.27 (singlet, 6 H), 2.12 (triplet, 2 H), and 4.26 (triplet, 2 H) ppm. Draw the structure for A and give a stepwise mechanism that accounts for its formation.
- Compounds X has the formula C7H15Cl; Y is C7H15Br.X undergoes base-promoted E2 elimination to give a single alkene product Z. Y likewise reacts under similar conditions to give a single alkene product that is isomeric with ZCatalytic hydrogenation of Z affords 3-ethylpentane.X readily reacts in SN2 fashion with sodium iodide in acetone. Y does not undergo a similar SN2 reaction. Propose structures for X and Y.In an aqueous solution containing sodium bicarbonate, aniline reacts quickly withbromine to give 2,4,6-tribromoaniline. Nitration of aniline requires very strong conditions,however, and the yields (mostly m-nitroaniline) are poor.(a) What conditions are used for nitration, and what form of aniline is present under theseconditions?An ether extraction of nutmeg gives large quantities of trimyristin, a waxy crystalline solid of melting point 57 °C. The IRspectrum of trimyristin shows a very strong absorption at 1733 cm-1. Basic hydrolysis of trimyristin gives 1 equivalent ofglycerol and 3 equivalents of myristic acid (tetradecanoic acid).(a) Draw the structure of trimyristin.(b) Predict the products formed when trimyristin is treated with lithium aluminum hydride, followed by aqueous hydrolysis of the aluminum salts