Macmillan LearningTwo particles approach each other with equal and opposite speed, v. The mass of one particle is m, and the mass of the otherparticle is nm, where n is just a constant factor. Snapshots of the system before, during, and after the elastic collision are shown.mBeforenmWhat is the value of nCollisionVm,finalmn =AfterVnmAfter the collision, the first particle moves in the exact opposite direction with speed 2.95v, and the speed of the second particle,Unm,final, is unknown.nm,final

Answered: Image /qna-images/answer/c0257ba3-4fdc-43e5-a831-77c54eed161a.jpg

Two particles approach each other with equal and opposite speed, v. The mass of one particle is m, and the mass of the other particle is nm, where n is just a constant factor. Snapshots of the system before, during, and after the elastic collision are shown. Before nm What is the value of n Collision V m,final m n= After nm After the collision, the first particle moves in the exact opposite direction with speed 2.95v, and the speed of the second particle Unm, final, is unknown. nm,final

Two particles approach each other with equal and opposite speed, v. The mass of one particle is m, and the mass of the other particle is nm, where n is just a constant factor. Snapshots of the system before, during, and after the elastic collision are shown. Before nm What is the value of n Collision V m,final m n= After nm After the collision, the first particle moves in the exact opposite direction with speed 2.95v, and the speed of the second particle Unm, final, is unknown. nm,final

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter9: Linear Momentum And Collisions

Section: Chapter Questions

Problem 66P: Two particles of masses m1 and m2 , move uniformly in different circles of radii R1 and R2 R2 about...

See similar textbooks

Similar questions

Starting with equations m1v1=m1v1cos1+m2v2cos2 and 0=m1v1cos1+m2v2sin2 for conservation of momentum in the x- and y -directions and assuming that one object is originally stationary, prove that for an elastic collision of two objects of equal masses, 12mv12=12mv22+mv1v2cos(12) as discussed in the text.
A billiard ball moving at 5.00 m/s strikes a stationary ball of the same mass. Alter the collision, the first ball moves at 4.33 m/s at an angle of 30.0 with respect to the original line of motion, (a) Find the velocity (magnitude and direction) of the second ball after collision, (h) Was the collision inelastic or elastic?
A basketball with a mass of 0.62 kg falls vertically to the floor where it hits with a speed of 6 m/s. (We take the positive direction to be upward here.) The ball rebounds, leaving the floor with a speed of 4.5 m/s. (a) What impulse acts on the ball during its collision with the floor? (b) If the ball is in contact with the floor for 0.04 s, what is the average force of the ball on the floor?
The figure below shows a bullet of mass 200 g traveling horizontally towards the east with speed 400 m/s, which strikes a block of mass 1.5 kg that is initially at rest on a frictionless table. After striking the block, the bullet is embedded in the block and the block and the bullet move together as one unit. a. What is the magnitude and direction of the velocity of the block/bullet combination immediately after the impact? b. What is the magnitude and direction of the impulse by the block on the bullet? c. What is the magnitude and direction of the impulse from the bullet on the block? d. If it took 3 ms for the bullet to change the speed from 400 m/s to the final speed after impact, what is the average force between the block and the bullet during this time?
A tennis ball of mass 57.0 g is held just above a basketball of mass 590 g. With their centers vertically aligned, both balls are released from rest at the same time, falling through a distance of 1.20 m, as shown in Figure P6.45. (a) Find the magnitude of the basketballs velocity the instant before the basketball reaches the ground. (b) Assume that an elastic collision with the ground instantaneously reverses the velocity of the basketball so that it collides with the tennis ball just above it. To what height does the tennis ball rebound? Figure P6.45
(a) If two automobiles collide, they usually do not stick together. Does this mean the collision is elastic? (b) Explain why a head-on collision is likely to be more dangerous than other types of collisions.
a man of mass m1 = 70.0 kg is skating at v1 = 8.00 m/s behind his wife of mass m2 = 50.0 kg, who is skating at v2 = 4.00 m/s. Instead of passing her, he inadvertently collides with her. He grabs her around the waist, and they maintain their balance. (a) Sketch the problem with before-and-after diagrams, representing the skaters as blocks. (b) Is the collision best described as elastic, inelastic, or perfectly inelastic? Why? (c) Write the general equation for conservation of momentum in terms of m1, v1, m2, v2, and final velocity vf. (d) Solve the momentum equation for vf. (e) Substitute values, obtaining the numerical value for vf, their speed after the collision.
A 65.0-kg basketball player jumps vertically and leaves the floor with a velocity of 1.80 m/s upward, (a) What impulse does the player experience? (b) What force does the floor exert on the player before the jump? (c) What is the total average force exerted by the floor on the player if the player is in contact with the floor for 0.450 s during the jump?
Two automobiles of equal mass approach an intersection. One vehicle is traveling with velocity 13.0 m/s toward the east, and the other is traveling north with velocity v2i. Neither driver sees the other. The vehicles collide in the intersection and stick together, leaving parallel skid marks at an angle of 55.0 north of east The speed limit for both roads is 35 mi/h, and the driver of the northward-moving vehicle claims he was within the limit when the collision occurred. Is he telling the truth?
Check Your Understanding Suppose the initial velocities were not at right angles to each other. How would this change both the physical result and the mathematical analysis of the collision?
A car crashes into a large tree that does not move. The car goes from 30 m/s to 0 in 1.3 m. (a) What impulse is applied to the driver by the seatbelt, assuming he follows the same motion as the car? (b) What is the average force applied to the driver by the seatbelt?
The x-component of a force on a 46-g golf ball by a 7-iron versus time is plotted in the following figure: Find the x-component of the impulse during the intervals i. [0,50ms] , and ii. [50ms,100ms] Find the change in the x-component of the momentum during the intervals iii. [0,50ms] , and iv. [50ms,100ms]