Upon reaction of 1.27 g of copper sulfate with excess zinc metal, 0.351 g copper metal was obtained as an experimental result according to the equation: CuSO4(aq) + Zn(s) → Cu(s) + ZNSO4(aq) Before the experiment was carried out the theoretical yield calculation was completed to predict the maximum amount of copper that could be isolated. The answer was 0.506 g of Cu. What is the percent yield in standard notation? [report your answer to the tenths place, i.e. one decimal place.]

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section: Chapter Questions
Problem 143QRT: In a reaction, 1.2 g element A reacts with exactly 3.2 g oxygen to form an oxide, AOx; 2.4 g element...
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Upon reaction of 1.27 g of copper sulfate with excess
zinc metal, 0.351 g copper metal was obtained as an
experimental result according to the equation:
CusO4(aq) + Zn(s) → Cu(s) + ZnSO4(aq)
Before the experiment was carried out the
theoretical yield calculation was completed to
predict the maximum amount of copper that could
be isolated. The answer was 0.506 g of Cu.
What is the percent yield in standard notation?
[report your answer to the tenths place, i.e. one decimal
place.]
Transcribed Image Text:Upon reaction of 1.27 g of copper sulfate with excess zinc metal, 0.351 g copper metal was obtained as an experimental result according to the equation: CusO4(aq) + Zn(s) → Cu(s) + ZnSO4(aq) Before the experiment was carried out the theoretical yield calculation was completed to predict the maximum amount of copper that could be isolated. The answer was 0.506 g of Cu. What is the percent yield in standard notation? [report your answer to the tenths place, i.e. one decimal place.]
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