Use the Alternative formula for Variance to calculate the variance of the random variable in Table 11 k         Pr(X=k) -2          .2 -1          .2 0           .2 1           .2 2          .2

Let x represent the average annual salary of college and university professors (in thousands of dollars) in the United States. For all colleges and universities in the United States, the population variance of x is approximately ?2 = 47.1. However, a random sample of 18 colleges and universities in Kansas showed that x has a sample variance s2 = 86.1. Use a 5% level of significance to test the claim that the variance for colleges and universities in Kansas is greater than 47.1. Find a 95% confidence interval for the population variance. ased on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Since the P-value > ?, we fail to reject the null hypothesis.Since the P-value > ?, we reject the null hypothesis.    Since the P-value ≤ ?, we reject the null hypothesis.Since the P-value ≤ ?, we fail to reject the null hypothesis. (e) Interpret your conclusion in the context of the application. At the 5% level of significance, there is insufficient…

Find the value of variance in the Binomial distribution where there are 5 samples and p=0.3.

In a human population, the proportion of individuals with a certain disease is 0.10. if we select a sample of size 1000 from this population, determine the value of the variance of the sample proportion.