Use the data below, for 298.15 K, to calculate the following quantities for the decomposition of NH4l(s) to give NH3(g) and HI(g). (b) 4,S" at 298.15 K (a) 4, Hº at 298.15 K (d) Kat 298.15 K 4Hº /kJ mol-1 Š /JK-¹ mol-¹ (c) 4,G" at 298.15 K NH,l(s) -201.4 117 ↑ NH,(g) (a) The standard enthalpy of reaction at 298.15 K is A,H= 182 (b) The standard entropy of reaction at 298.15 K is A,S = 282.4 (c) The standard Gibbs energy of reaction at 298.15 K is A,G= 97.80 -45.9 192.8 Enter your answers in the specified units. Do not include units with your answers. kJ mol-¹. JK¹ mol-¹. kJ mol-¹. HI(g) 26.5 206.6

Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
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Chapter17: Electrochemistry
Section: Chapter Questions
Problem 49E
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Use the data below, for 298.15 K, to calculate the following quantities for the decomposition of NH4l(s) to give
NH3(g) and HI(g).
(a) AH at 298.15 K
(d) Kat 298.15 K
4₁H
/kJ mol-1
(b) 4,Sº at 298.15 K
5
/JK-¹ mol-¹
(c) 4, Gº at 298.15 K
NH,l(s)
-201.4
117
↑
NH3(g)
-45.9
192.8
Enter your answers in the specified units. Do not include units with your answers.
kJ mol-¹.
JK¹ mol-¹.
(a) The standard enthalpy of reaction at 298.15 K is A, H° = 182
(b) The standard entropy of reaction at 298.15 K is A,Sº = 282.4
(c) The standard Gibbs energy of reaction at 298.15 K is A, G = 97.80
(d) The value of the thermodynamic equilibrium constant at 298.15 K is K= Number
kJ mol-¹.
HI(g)
26.5
206.6
Transcribed Image Text:Use the data below, for 298.15 K, to calculate the following quantities for the decomposition of NH4l(s) to give NH3(g) and HI(g). (a) AH at 298.15 K (d) Kat 298.15 K 4₁H /kJ mol-1 (b) 4,Sº at 298.15 K 5 /JK-¹ mol-¹ (c) 4, Gº at 298.15 K NH,l(s) -201.4 117 ↑ NH3(g) -45.9 192.8 Enter your answers in the specified units. Do not include units with your answers. kJ mol-¹. JK¹ mol-¹. (a) The standard enthalpy of reaction at 298.15 K is A, H° = 182 (b) The standard entropy of reaction at 298.15 K is A,Sº = 282.4 (c) The standard Gibbs energy of reaction at 298.15 K is A, G = 97.80 (d) The value of the thermodynamic equilibrium constant at 298.15 K is K= Number kJ mol-¹. HI(g) 26.5 206.6
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