Use the tabulated electrode potentials to calculate K for the oxidation of iron by H++ (at 25°C): 2Fe(s)+6H+(aq)→2Fe3

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter17: Electrochemistry And Its Applications
Section: Chapter Questions
Problem 92QRT
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Use the tabulated electrode potentials to calculate K for the oxidation of iron by H++ (at 25°C):

2Fe(s)+6H+(aq)→2Fe3+(aq)+3H2(g)

TABLE 18.1
Standard Reduction Potentials at 25°C
E°
Reduction Half-Reaction
(V)
2 F (aq)
Stronger
oxidizing
agent
F2(g) +
H2O;(aq) + 2 H*(aq) + 2 e-
MnO, (aq) + 8 H*(aq) + 5 e
Cl2(8) + 2 e-
Cr,0, (aq) + 14 H*(aq) + 6 e
O:(8) + 4 H*(aq) + 4 e-
Br2(1) + 2 e
Ag*(aq) + e
Fe*(aq) + e
Oz(g) + 2 H*(aq) + 2 e
I2(s) + 2 e-
O:(g) + 2 H,O(1) + 4 e-
Cu2*(aq) + 2 e
Sn*(aq) + 2 e
2 e
2.87
Weaker
reducing
agent
2 H;O(I)
1.78
→ Mn2 (aq) + 4 H,O(1)
→2 CI(aq)
→2 Cr* (aq) + 7 H;O()
→ 2 H;O(I)
→2 Br (aq)
→ Ag(s)
Fe2*(aq)
(bv)O°H
2 1 (aq)
→ 4 OH"(aq)
1.51
1.36
1.33
1.23
1.09
0.80
0.77
0.70
0.54
0.40
Cu(s)
0.34
• Sn²*(aq)
0.15
2 H*(aq) + 2 e-
Pb2*(aq) + 2e
Ni2*(aq)
Pb(s)
Ni(s)
→ Cd(s)
→ Fe(s)
-0.13
+ 2 e
Cd2*(aq) + 2 e
Fe2*(aq) + 2 e
Zn2*(aq) + 2 e-
2 H,O() + 2 e
Al"(aq) + 3 e
Mg*(aq) + 2e
Na*(aq) + e-
Li*(aq) + e
-0.26
-0.40
-0.45
>Zn(s)
→ H2(g) + 2 OH(aq)
→ Al(s)
→ Mg(s)
→ Na(s)
→ Li(s)
-0.76
-0.83
-1.66
-2.37
Stronger
reducing
agent
Weaker
-2.71
oxidizing
agent
-3.04
Transcribed Image Text:TABLE 18.1 Standard Reduction Potentials at 25°C E° Reduction Half-Reaction (V) 2 F (aq) Stronger oxidizing agent F2(g) + H2O;(aq) + 2 H*(aq) + 2 e- MnO, (aq) + 8 H*(aq) + 5 e Cl2(8) + 2 e- Cr,0, (aq) + 14 H*(aq) + 6 e O:(8) + 4 H*(aq) + 4 e- Br2(1) + 2 e Ag*(aq) + e Fe*(aq) + e Oz(g) + 2 H*(aq) + 2 e I2(s) + 2 e- O:(g) + 2 H,O(1) + 4 e- Cu2*(aq) + 2 e Sn*(aq) + 2 e 2 e 2.87 Weaker reducing agent 2 H;O(I) 1.78 → Mn2 (aq) + 4 H,O(1) →2 CI(aq) →2 Cr* (aq) + 7 H;O() → 2 H;O(I) →2 Br (aq) → Ag(s) Fe2*(aq) (bv)O°H 2 1 (aq) → 4 OH"(aq) 1.51 1.36 1.33 1.23 1.09 0.80 0.77 0.70 0.54 0.40 Cu(s) 0.34 • Sn²*(aq) 0.15 2 H*(aq) + 2 e- Pb2*(aq) + 2e Ni2*(aq) Pb(s) Ni(s) → Cd(s) → Fe(s) -0.13 + 2 e Cd2*(aq) + 2 e Fe2*(aq) + 2 e Zn2*(aq) + 2 e- 2 H,O() + 2 e Al"(aq) + 3 e Mg*(aq) + 2e Na*(aq) + e- Li*(aq) + e -0.26 -0.40 -0.45 >Zn(s) → H2(g) + 2 OH(aq) → Al(s) → Mg(s) → Na(s) → Li(s) -0.76 -0.83 -1.66 -2.37 Stronger reducing agent Weaker -2.71 oxidizing agent -3.04
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