Use iterators to add up all of the numbers in a vector. #include using namespace std; double accumulate(const vector& v) { (...) }

Complete the following function that counts the even numbers in a 2D vector of integers. int count_evens(const std::vector<std::vector<int>>& v) { // Add your code... } Please add output screenshot!

def dotProduct(Vs): V1 #get first vector from Vs ......... V2 #get second vector from Vs #check if they are in the same length ......... if ......... ...... ... #complete as needed ......... for in ...... ... ......... . dp #dp: dot-product ......... #complete as needed #u = (-2 4 -2) and v = (-3 6 3) u = . .; #setup u an v as a numpy array V Vc = [. ., #test the function using u and v print (.) #print "Dot-product of vectors is

Can you help me with the second two phases because I have the first two done. My code is provided below: First Phase CODE #include <iostream>#include <vector>using namespace std; void print(vector<double> times){    int size = times.size();    for(int i=0;i<size;i++){        cout<<times[i]<<" ";    }    cout<<endl;    return;} int main(){    vector<double> times;    double input;        while(cin>>input){        times.push_back(input);    }        print(times);    return 0;} Second Phase CODE #include <iostream>#include <string>#include <vector>#include <fstream>#include <sstream> using namespace std; void display(vector<int> times) { cout << "Your swim times are: "; for (int i = 0; i < times.size(); i++) {  if (i < times.size() - 1) {   cout << times[i] << ", ";  }  else {   cout << times[i];  } } cout << endl;} int main() { vector<int> times; int time;…