Using Assembly code in (emu8086) Write program that display your decimal number then add Number four 4 to your decimal number?

write a python code that decodes the coloured bands on a resistor.Each colour band printed on a resistor has a corresponding numeric value, as shown in the table below: Colour Numeric value black 0 brown 1 red 2 orange 3 yellow 4 green 5 blue 6 violet 7 grey 8 white 9 To calculate the total resistance value, the following formula should be used: resistance=(10a+b)⋅10^c where a, b, and c are the numeric values of the first, second, and third colour bands respectively. For example, let's say that the colour bands on a resistor are red-green-orange. In this case, a=2, b=5, and c=3 (using the table). Hence the resistance value is 25000 ohms: resistance=(10*2+5) x 10^3=25000 ohms Your task is to write a program which asks the user to input the three colour bands. The program should then calculate and output the resistance value indicated by the bands. As part of your solution, you must define and use a function named colour_to_number. This function should take…

Use the program below: Modify the program that will test whether or not the expression evaluates to a negative or positive number. This is in MIPS Assembly Language Sample OUTPUT: The output is 14 output is positive. THIS DOES NOT SHOW IN CODE       #Evaluate the expression: 4x^2 - 8x + 2 .data prompt: .asciiz "Enter an input for x to evaluate 4x^2 - 8x + 2: " output: .asciiz "The output is " .text main: li$v0,4#output the prompt for user la$a0,prompt syscall   li$v0,5#input the number and save it to $s0 syscall move $s0,$v0   #square the input #lw$t0, ($s0) mul$t0, $s0, $s0 #multiply by 4 mul$t0, $t0, 4 #multiply input by -8 #lw $t2, ($s0) mul $t2, $s0, -8 #add it all add$t0, $t0, $t2 add$t0, $t0, 2   li$v0,4#print the output label la$a0,output syscall   li$v0,1#output the number that was entered move$a0,$t0#could also use lw $a0, $s0. Pseudo code syscall   li$v0, 0xB #print newline, 0xB = 11  #which is the system call to print a single character    la$a0, 0xA#0xA is the newline…

There are three single precision floating point numbers, numA, numB and numC. Write a piece of code in MIPS assembly language  that compares  two numbers numA and numb, if numB  is greater than numA, add them and save the result in numC. Otherwise save 0 in numC.