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Given : Mass of Zn(C2H3O2)2.2H2O reacting = 2.19 g
Molar mass of Zn(C2H3O2)2.2H2O = Atomic mass of Zn + ( Atomic mass of C X 2 + Atomic mass of H X 3 + Atomic mass of O X 2 ) X 2 + Molar mass of H2O X 2
=> Molar mass of Zn(C2H3O2)2.2H2O = 65.4 + (12 X 2 + 1 X 3 + 16 X 2) X 2 + 18 X 2 = 219.4 g/mol.
Since mass = moles X molar mass
=> 2.19 = moles of Zn(C2H3O2)2.2H2O reacting X 219.4
=> Moles of Zn(C2H3O2)2.2H2O reacting = 0.010 mol approx.
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