• Using "join" function for the string • The join function is a more flexible way for concatenating string. • With join function, you can add any character into the string.
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- Create a c++ find function that finds a word or phrase within a string. This function should accept the string, and the word or phrase to look for. It should return a list of the character elements where the start of the word/phrase is found in the string. however, this list of elements must be returned as a char* type (not as a string nor individual integers). EX testString) Hello I am Hello Today I am Named John. I like to say Hello. input word string = Hello; find(String, word) //This function call should return 0, 11, 54 because H of Hello is the 0th character, 11th character, and 54th character in testString.# PART 1 - Complete the function below to deocompose# a compound formula written as a string# in a dictionary###################################################### def mol_form(compound_formula): """(str) -> dictionary When passed a string of the compound formula, returns a dictionary with the elements as keys and the number of atoms of that element as values. >>> mol_form("C2H6O") {'C': 2, 'H': 6, 'O': 1} >>> mol_form("CH4") {'C': 1, 'H': 4} """python exercise: Write a Python function called get_top_students that takes the list of dictionaries as input and returns a dictionary containing the name and GPA of the top two students in the list. Each dictionary has the following keys: "name", "age", "major", and "gpa".
- This code is a part of a C dictionary. Please write the code for the below requirements. dict_get Next, you will implement: char* dict_get (const dict_t* dict, const char* key); This function goes through the list given by dict. If you use the above structure, this means starting at el = dict->head and checking each time whether the key at el is key; if it is not, we set el = el->next, until either key is found, or we reach el == NULL. To compare key with el->key, we need to compare one by one each character in key with those in el->key. Remember that strings in C are just pointers (memory addresses) to the first character in the string, so comparing el->key == key will not do what you want. So how do you even get the length of a string s? You would start at memory location s and advance as long as the byte at s (i.e. *s) is not the end-of-string marker (\0, the NULL character). This can get a bit messy, so luckily, you are allowed to use the string comparison…Data structures dict_from_string(dict_str:str)->dict This function will be given a single parameter, a string representing a dictionary. Your job is to convert the string into an actual dictionary and return the dictionary. Make sure all key-value pairs in the string exist in the newly created dictionary. The string will contain only numbers or single letters as key values pairs. Make sure all letters are kept as strings and all numbers are converted to integers in the newly created dictionary. Example: String Input: '{9: 'V', 'G': 0, 'M': 9, 'u': 3, 2: 'o', 8: 'u', 'q': 9, 'D': 1}' Expected: {9: 'V', 'G': 0, 'M': 9, 'u': 3, 2: 'o', 8: 'u', 'q': 9, 'D': 1} String Input: '{10: 'D', 1: 'Z', 5: 'a'}' Expected: {10: 'D', 1: 'Z', 5: 'a'} String Input: '{'M': 2, 'V': 0, 3: 'x', 6: 'J', 5: 'J', 7: 'T', 8: 'P', 4: 'q', 1: 'h'}' Expected: {'M': 2, 'V': 0, 3: 'x', 6: 'J', 5: 'J', 7: 'T', 8: 'P', 4: 'q', 1: 'h'} String Input: '{3: 'D', 10: 'T', 7: 'm', 'u': 9, 't': 5, 6: 'Z', 'H': 10, 'B':…City and State. Extract the city name and state from strings like “Utica, NY” and “Los Angeles, CA”. Assume the state is always the last two characters in the string, the city name has at least one character, there is a comma following the city name, and a single space after the comma. Use the split method to separate the city name from the state (Notice the city name will still have a comma at the end). The following attachement is a sample execution:
- (C++) 9. True/False: the strcpy() function will make sure there is enough memory allocated in the destination string before copying C-strings 10. True/False: when creating a string object, you must dynamically allocate enough bytes to hold the string 11. Consider the following statement, assuming goAgain is a valid char. Rewrite it using toupper() or tolower() if (goAgain == 'y' || goAgain == 'Y') 12. Write a C++ function which accepts a pointer to a C-string as its argument. It should return the number of words in the C-string. For example, for the C-string “The Giants won the pennant!” your function should return 5. You may assume the parameter passed is a pointer to a valid, null-terminated C-string with no newlines or tabs, exactly one space separates each word, and there is at least one word. int wordCounter(char* str)// Fix this program that works// Use welcome function that display the message in diffreent color// Use Draw function to diplay table in gree/yellow// Remove, add, any code that you believe is not useful#include <iostream>#include <windows.h> using namespace std;char mat[3][3];void table(); //function to print the tablevoid welcome(); //function for welcome screenint main(){ int i, j, m, n, sum = 0; char ch; welcome(); system("pause"); for (m = 0; m < 3; m++) for (n = 0; n < 3; n++) mat[m][n] ='W'; table(); while (sum < 10) { //================== for player 1 =================== cout << "Player 1 is X Choose the position : "; cout << "Row:"; cin >> i; cout << "Coloumn:"; cin >> j; //============== if position is wrong ============ for (; i > 3 || i < 1 || j>3 || j < 1 || ('x' == mat[i - 1][j - 1] || 'o'…Complete the string_lengths(my_list) function below. It takes a list of strings, and it should return a dictionary that maps each string to the length of the string. For example, string_lengths(['kool', 'kitty', 'kat' ]) should return the dictionary {'kool': 4, 'kitty': 5, 'kat': 3}.
- Dec2Hex function : def decimal_to_hex(number): hex_map = {0: '0', 1: '1', 2: '2', 3: '3', 4: '4', 5: '5', 6: '6', 7: '7', 8: '8', 9: '9', 10: 'A', 11: 'B', 12: 'C', 13: 'D', 14: 'E', 15: 'F'} hex_digits = [] while number > 0: hex_digits.append(hex_map[number % 16]) number //= 16 # Reverse the order of the hex digits and join them to form the final hex string hex_string = ''.join(reversed(hex_digits)) return f'0x{hex_string}' if hex_string else '0x0' Perform a Profile of your Dec2Hex function. Write a function that takes a timedate object as a parameter andcalculates the number of years from NOW to the time in the timedateobject. Add unit-testing code to your Dec2Hex exercise, and then perform aUnit test of the updated Dec2Hex code.Program - Python (problem under code) This is my code for a dictionary of student's test scores. def main():#Create a dictionary with name as key#Marks as the list of valuesstudent_dictionary=\{'Brian': [94, 89, 92],'Rachel': [100,90,65],'Jon': [67.5,95,100],'Brit': [0,78,80] ,'Gret': [65,100,78],'Andrea': [55.5,67,79]}#Loop that print name and list of marksfor key, values in student_dictionary.items():print('Name: ', key, " , Marks:", values)#Call main functionif __name__ == '__main__':main() Problem: Find and print out Rachels second score (should be a 90)Computer Science create function getRandomSymptom() returns int as begin declare @id int; select top 1 @id = id from symptom order by newid(); return @id; end; Invalid use of a side-effecting operator 'newid' within a function. HOW TO CORRECT THIS ERROR?