Using the 99% level of confidence, what is the confidence interval for proportion of students attending home football games?

Q: In a survey of 2279 ​adults, 729 say they believe in UFOs. Construct a 90% confidence…

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Q: In a survey of 3005 adults aged 57 through 85 years, it was found that 81.7% of them used at least…

A: Given :  n = 3005 p̂=0.817

Q: 2. A nutritionist wants to know the population proportion of Grade 1 learners who eat vegetables.…

A: We have given thatn = 1200x = 200p̂ = x/n = 200/1200 = 0.167Significance level (α) = 1 - 0.95 = 0.05

Q: In a survey of 2344 ​adults, 715 say they believe in

A: Given that there are 2344 adults and 715 say they believe in UFOs. Consider the sample proportion,…

Q: We surveyed 53 people in an attempt to determine the proportion of Americans who lease a vehicle. 13…

A: The proportion of sample Americans who lease a vehicle is, Thus, the proportion of sample Americans…

Q: In each of Exercises, use the one-proportion plus-four z-interval procedure to find the required…

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Q: In a survey of 1,200 social media users, 56% said it is not okay to be friends with your boss.…

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Q: In a recent poll, 280 people were asked if they liked dogs, and 51% said they did. Find the margin…

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Q: Use the formula for a Confidence Interval for Two Proportions to calculate a 95% confidence interval…

A: Confidence interval: The (1-α)100 % confidence interval for proportion p1 – p2 is given by,

Q: In a survey of 3234 adults aged 57 through 85​ years, it was found that 88.9% of them used at least…

A:

Q: We would like to know: "What percentage of college students read the college newspaper every day?"…

A: It is provided that there is random sample of 500 college students in which 231 students said that…

Q: Is the difference between the two indicators significant at the 95% confidence level?

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Q: A magazine provided results from a poll of 2000 adults who were asked to identify their favorite…

A: A magazine provided results from a poll of 2000 adults who were asked to identify their favorite…

Q: In a survey of 50,00 people, 80% indicated that they listened to their favorite radio station…

A: Hern= 5000 P^ = 0.80 We have to construct 95% ci for p

Q: In a survey of 300 random households in a particular village, mothers have been asked if they use…

A: From the provided information, Sample size (n) = 300 From which 76 said Yes, they use cellphones to…

Q: In one city, 59.6% of the 1500 students surveyed said they eat at the school cafeteria. Find the 95%…

A: Given, Sample size=n=1500 p^=0.596 α=0.05

Q: Find a 95% confidence interval for the proportion of renters.

A: It is given that  Favourable cases, X = 360 Sample size, n = 600 Confidence interval = 95%

Q: The confidence interval was (22, 26) What was the point estimate? What was the margin of error?

A: Given confidence interval was (22, 26)

Q: In a survey of 4061 ​adults, 738 say they have seen a ghost. Construct a​ 99% confidence interval…

A: In this question, it has been given that 738 people out of 4061 people have seen the ghost, we have…

Q: In a recent poll, 600 people were asked if they liked dogs, and 58% said they did. Find the margin…

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Q: In a survey of 1000 people, 850 said they would not to travel to Disney World this summer. Construct…

A: Given: n=1000 and x=850 Then,p^=xn=8501000=0.85

Q: What proportion of college students earn their undergraduate degrees in four years? A college…

A: The formula of the margin of error when the limits given are,

Q: The general social survey for 2002 noted that 192 of the 1458 respondents were black or…

A: Sample proportion = p p = 192/1458 = 0.1317 n = 1458

Q: A magazine provided results from a poll of 1000 adults who were asked to identify their favorite…

A: Given: Number of adults = 1000 Percentage of people who chose chocolate = 13% Margin of error =…

Q: In a recent poll of 1100 randomly selected home delivery truck drivers, 26% said they had…

A: From the provided information, Sample size (n) = 1100 26% said they had encountered an aggressive…

Q: An ice cream shop wants to know how many customers enjoy their newest flavor. 200 randomly selected…

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Q: A research institute poll asked respondents if they felt vulnerable to identify a theft. In the poll…

A: Given,n=1000x=501p^=xnp^=5011000=0.5011-p^=1-0.501=0.499α=1-0.99=0.01α2=0.005Z0.005=2.58    (from…

Q: Out of 500 people sampled, 455 had kids. The best point estimate for p is . The margin of error…

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Q: What is z* for a 92% confidence level?

A: To find value of Z* for a 92% confidence level ??

Q: a magazine provided results from a poll of 2000 adults who were asked to identify their favorite…

A: Given Information: A magazine provided results from a poll of 2000 adults who were asked to identify…

Q: A marketing study by Ford Motor Company finds that 320 of the 650 buyers of compact cars were women.…

A: Let the population proportion of women who bought compact cars be P Given:         Sample size n =…

Q: What is the difference between the different confidence interval formulas?

A: Confidence interval is the estimate of the interval of an unknown population parameter. It provides…

Q: A study was being done to estimate the proportion of students who receive financial aid. If the…

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Q: Construct a 95% confidence interval for the proportion of college students who say they own their…

A: Given : n=410 , X=155  , α=0.05 We want to find the 95% confidence interval for the proportion of…

Q: Find a 90% confidence interval for the true proportion of people that eat frog legs, if in a sample…

A: Given, n = 732 p = 0.65 1 - α = 0.90α = 0.1α2 = 0.05   To find, 90% confidence interval for the true…

Q: The pizza Shop wanted to determine what proportion of its customers ordered an only cheese pizza.…

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Q: Would represent a 90% confidence interval for the average highway mileage of all Smart Cars?

A: we need to find the confidence interval of the mean GIVEN mean=47 S.D=5 n=15

Q: The confidence interval was (64, 76) What was the point estimate? What was the margin of error?

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Q: Michelle, a student studying music, randomly sampled fellow music majors and asked whether they…

A: Given information- Confidence interval = (0.09, 0.26) We have to find margin of error. We know that-…

Q: The Pizza Shop wanted to determine what of its customers ordered an only cheese pizza. Out of 90…

A:

Q: A recent study of 750 internet users in Europe found that 35% of internet users were women. What is…

A: It is given that the study of 750 internet users in Europe found that 35% of internet users were…

Q: The owner of the Gas station wishes to determine the proportion of customers who use credit card. he…

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Q: A survey of 800 women shoppers found that 17% of them shop on impulse. what is 98% confidence…

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Q: A magazine provided results from a poll of 1500 adults who were asked to identify their favorite…

A:

Q: When 500 college students were surveyed, 30% said that they own their car. Construct a 95%…

A: Here we want to find the 95% confidence interval.

Q: Aston’s Career Service wants to find out what proportion of Aston’s students work in a part-time…

A: From the given information, Population proportion = p = 60% = 0.60 Margin of error = E = 4% = 0.04…

Q: In a survey of 2273 ​adults, 728 say they believe in UFOs.   Construct a 99% confidence interval for…

A: Given Information: Sample size (n) = 2273 Out of which X = 728 adults say they believe in UFOs. To…

Q: A magazine provided results from a poll of 1000 adults who were asked to identify their favorite…

A: Given,sample size(n)=1000sample proportion(p)=0.14

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.