Using the balanced equation for the synthesis of acrylonitrile (below), determine the amount of acrylonitrile that can be produced under the following conditions and the percent yield for this reaction. 2C3H6(g) + 2NH3(g) + 302(g) → 2C;H;N(g) + 6H20(g) 4. NEXT > The local chemical company makes a batch of acrylonitrile using 1.00 kg of propylene (C3H6, MW 42.08 g/mol), 1.50 kg of ammonia (NH, MW 17.03 g/mol) and 2.00 kg of oxygen (O2, MW 32.00 g/mol). Set up the table below that represents 100% yield with the given reaction conditions. Ignore the water side product. 2C3H6(g) 2NH3(g) 302(g) 2C,H;N(g) Before (mol) Change (mol) After (mol)
Using the balanced equation for the synthesis of acrylonitrile (below), determine the amount of acrylonitrile that can be produced under the following conditions and the percent yield for this reaction. 2C3H6(g) + 2NH3(g) + 302(g) → 2C;H;N(g) + 6H20(g) 4. NEXT > The local chemical company makes a batch of acrylonitrile using 1.00 kg of propylene (C3H6, MW 42.08 g/mol), 1.50 kg of ammonia (NH, MW 17.03 g/mol) and 2.00 kg of oxygen (O2, MW 32.00 g/mol). Set up the table below that represents 100% yield with the given reaction conditions. Ignore the water side product. 2C3H6(g) 2NH3(g) 302(g) 2C,H;N(g) Before (mol) Change (mol) After (mol)
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter10: Fuels, Organic Chemicals, And Polymers
Section: Chapter Questions
Problem 89QRT
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