Using the Link codes, write a program to implement the following operations: 1) Create a list that has the following elements: <8; 23; 65; 5; 30 >; 2) Print the elements of the list; 3) Delete the element with value 65, and then print the e lements of the list. Output Example: <|8 23 65 5 30 > <8 23 |5 30 >
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Types of Linked List
A sequence of data elements connected through links is called a linked list (LL). The elements of a linked list are nodes containing data and a reference to the next node in the list. In a linked list, the elements are stored in a non-contiguous manner and the linear order in maintained by means of a pointer associated with each node in the list which is used to point to the subsequent node in the list.
Linked List
When a set of items is organized sequentially, it is termed as list. Linked list is a list whose order is given by links from one item to the next. It contains a link to the structure containing the next item so we can say that it is a completely different way to represent a list. In linked list, each structure of the list is known as node and it consists of two fields (one for containing the item and other one is for containing the next item address).
C++
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- Topic: Singly Linked ListImplement the following functions in C++ program. Read the question carefully. (See attached photo for reference) int removeAt(int pos) Removes the number in the posth position of the list and returns the element removed. Performing removeAt(3) in the example list will remove the 3rd element of the linked list and the updated list will be: 10 -> 30 -> 50 When the value of pos is greater than the size or less than one, return -1. int removeAll(int num) Removes all instances of num in the linked list and returns the number of instances removed. In this list 10 -> 10 -> 20 -> 30 -> 10, performing removeAll(10) will remove all three 10's and the list will look like this: 20 -> 30. Then, it will return the number of instances removed, in this case, 3. int contains(int num) This will return the position of the first instance of the element num in the list. If num is not found, return 0. In the example, having the method contains(30) will…def normal (L): '' '(list of int) -> list Precondition: len (L)> = 1 This function must return a new list R which has the same contents of L except where there is a sequence of consecutive zeros, the list R must have only one zero such that in the examples: >>> normal ([1,2,0,0,0,3,0]) [1, 2, 0, 3, 0] >>> normal ([1,2,0,0,0,3,0,0,0,0]) [1, 2, 0, 3, 0] >>> normal ([0,0,1,0,2,0,0,0,3,0,0,0,0,0]) [0, 1, 0, 2, 0, 3, 0] >>> normal ([1,2,2,0,3,3,3,0]) [1, 2, 2, 0, 3, 3, 3, 0] '' ' [1, 2, 0, 3, 0] >>> tanganyika([1,2,0,0,0,3,0,0,0,0]) [1, 2, 0, 3, 0] >>> tanganyika([0,0,1,0,2,0,0,0,3,0,0,0,0]) [0, 1, 0, 2, 0, 3, 0] >>> tanganyika([1,2,2,0,3,3,3,0]) [1, 2, 2, 0, 3, 3, 3, 0] ''' Please: Do not use dictionaries.- Do not use sets- Do not use 'break'.- You cannot import a library or other moduleWrite the code to create a linked list using c++ Include the following functionality: Insert at the head or tail of the list. Delete one item (based on an entered value) or all of the list. Print out the linked list. Use the following class and struct to create your linked list: #include <iostream> #include <algorithm> using std::cout; using std::endl; using std::swap; struct Node { int m_data; Node* m_next; }; class LList { public: LList(); LList(int data); LList(const LList& copy); LList(LList&& move) noexcept; ~LList(); int getData(); Node* getNext(); void setData(int data); void insertHead(int data); void insertTail(int data); void deleteNode(int data); void setNext(LList* next); LList& operator = (const LList& copy); LList& operator = (LList&& move) noexcept; void printList(); private: Node* head; };
- struct node{int num;node *next, *before;};start 18 27 36 45 54 63 The above-linked list is made of nodes of the type struct ex. Your task is now to Write a complete function code to a. Find the sum of all the values of the node in the linked list. b. Print the values in the linked list in reverse order. Use a temporary pointer temp for a and b. i dont need a full code just the list partJAVA CODE PLEASE Linked List Practice ll by CodeChum Admin Write a function printNodes that takes in the head of a linked list and prints all the values of that linked list using a while loop. Print the values separated by a [space]->[space] In the main function, write a program that asks the user to input five integers and assign these values to the nodes. Arrange the nodes in ascending order first before printing them using the printNodes function. Input 1. One line containing an integer 2. One line containing an integer 3. One line containing an integer 4. One line containing an integer 5. One line containing an integer Output Enter·number·1:·1 Enter·number·2:·2 Enter·number·3:·3 Enter·number·4:·4 Enter·number·5:·5 1·->·2·->·3·->·4·->·5Implement the following function using C++ remove_redundant() This method will clear out the duplicate numbers in your linked list. It is also imperative that you will use an instance of this Linked List class to hold the numbers that you have already checked and use the methods in this instance. In the example 10 -> 10 -> 20 -> 30 -> 10, calling remove_redundant() will remove the other 2 10's that occurred later, hereby making the list 10 -> 20 -> 30. Limitation: You cannot have a nested loop here nor use methods that employ loops as the performance of our linked list will suffer.
- 6.34 LAB: Contact list C++ A contact list is a place where you can store a specific contact with other associated information such as a phone number, email address, birthday, etc. Write a program that first takes as input an integer N that represents the number of word pairs in the list to follow. Word pairs consist of a name and a phone number (both strings). That list is followed by a name, and your program should output the phone number associated with that name. Ex: If the input is: 3 Joe 123-5432 Linda 983-4123 Frank 867-5309 Frank the output is: 867-5309 Your program must define and call the following function. The return value of GetPhoneNumber is the phone number associated with the specific contact name.string GetPhoneNumber(vector<string> nameVec, vector<string> phoneNumberVec, string contactName) Hint: Use two vectors: One for the string names, and the other for the string phone numbers.Topic: Singly Linked ListImplement the following functions in C++ program. Read the question carefully. Below are the "CODE THAT NEEDS TO BE IMPROVED" or "NOT FINAL CODE" (See attached photo for reference) int add(int num) This will add the element num into the linked list and return the position of the newly-added element. In the above example, having add(60) will return 5 as it is the fifth position in the list. int remove(int num) This will remove the first instance of the element and return the position of the removed element. In the above example, having remove(40) will return 3 as 40 was the third element in the linked list before having removed. int get(int pos) This method will get the element at the specified position. This will return -1 if the specified position is invalid. int add(int num) { addTail(num); return index; } int remove(int num) { node* currnode = head; node* prevnode = NULL;…C++The List class represents a linked list of dynamically allocated elements. The list has only one member variable head which is a pointer that leads to the first element. See the following code for the copy constructor to List. List (const List & list) { for (int i = 0; i <list.size (); i ++) { push_back (list [i]); } } What problems does the copy constructor have? Select one or more options: 1. List (const List & list) {} does not define a copy constructor. 2. The list parameter should not be constant. 3. The new elements will be added to the wrong list. 4. Copy becomes shallow rather than deep. 5. The copy will create dangling pointers. 6. Copying will create memory leaks. 7. The condition must be: i <size () 8. head is never initialized.
- 8.14 LAB: Mileage tracker for a runner Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is: 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 the output is: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 Main.cpp: #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the PrintNodeData()…8.14 LAB: Mileage tracker for a runner Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is: 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 the output is: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 Main.cpp: #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the PrintNodeData()…8.14 LAB: Mileage tracker for a runner Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is: 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 the output is: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 Main.cpp #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the PrintNodeData()…