Using the table above and the mRNA transcript AUG-CUC-UAC-AAG-UAG, choose the false statement: XXX The protein encoded for by the transcript above would appear as met-leu-tyr-glu. The segment of DNA from which the mRNA segment above was transcribed would have had the following sequence: TAC-GAG-ATG-TTC-ATC. a mutation that changes the codon UAC to UAU wouldn't have any effect on the primary structure of the protein it codes for. A TRNA with the anticodon UUU will carry the amino acid lysine (Lys).

Using the table above and the mRNA transcript AUG-CUC-UAC-AAG-UAG, choose the false statement: XXX The protein encoded for by the transcript above would appear as met-leu-tyr-glu. The segment of DNA from which the mRNA segment above was transcribed would have had the following sequence: TAC-GAG-ATG-TTC-ATC. a mutation that changes the codon UAC to UAU wouldn't have any effect on the primary structure of the protein it codes for. A TRNA with the anticodon UUU will carry the amino acid lysine (Lys).

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter9: Gene Expression And Gene Regulation

Section: Chapter Questions

Problem 17QP: Given the following mRNA, write the double-stranded DNA segment that served as the template....

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Given the following mRNA, write the double-stranded DNA segment that served as the template. Indicate both the 5 and the 3 ends of both DNA strands. Also write out the tRNA anticodons and the amino acid sequence of the protein encoded by the mRNA message. DNA: mRNA: 5-CCGCAUGUUCAGUGGGCGUAAACACUGA-3 protein: tRNA:
The amino acids, in one-letter symbols and no spaces, coded by the following mRNA sequence is 5’ AAUGGAACGUCGGUACUGCCAUCGCAUUAGUACCAUGGCAAGCUGAAGC 3’
Given the following mRNA transcript: 5’-UUUGGCAUGGGUAUCGUAGAGAUGGAAUUCAUAGUGGAGUAA-3’ What is the one-letter abbreviation of the protein product of the mRNA transcript?
Given the following mRNA transcript: 5’-UUUGGCAUGGGUAUCGUAGAGAUGGAAUUCAUAGUGGAGUAA-3’ Determine the DNA template from which the mRNA was transcribed.
Referring to the genetic code presented in Figure , give the aminoacids specified by the following bacterial mRNA sequences. Q. 5′ –GUACUAAGGAGGUUGUAUGGGUUAGGGG ACAUCAUUUUGA–3′
Determine the amino acid sequence for a polypeptide coded for by the following mRNA transcript (written 5'-> 3'): AUGCCUGACUUUAAGUAG
The code for a fully functional protein is actually coming from an mRNA transcript that has undergone post transcriptional processing which is essentially way too different from the original code in the DNA template. Given: Cytosine; a Protein with known amino acid sequence (amino acid sequence given below) MATIVNTKLGEHRGKKRVWLEGQKLLREGYYPGMKYDLELKDSQVVLRVKEEGKFTISKRERNGRVSPII DLTVQELATVFDGVEMLRVFIRNGAIVISAHHQQERVIERVNRLISKLENGESLSVCSLFHGGGVLDKAI HAGFHKAGIASAISVAVEMEGKYLDSSLANNPELWNEDSIVIESPIQAVNLSKRPPQVDVLMGGIPCTGA SKSGRSKNKLEFAESHEAAGAMFFNFLQFVEALNPAVVLIENVPEYQNTASMEVIRSVLSSLGYSLQERI LDGNEFGVIERRKRLCVVALSHGIDGFELEKVQPVRTKESRIQDILEPVPLDSERWKSFDYLAEKELRDK AAGKGFSRQLLTGDDEFCGTIGKDYAKCRSTEPFIVHPEQPELSRIFTPTEHCRVKGIPEELIQGLSDTI AHQILGQSVVFPAFEALALALGNSLWSWVGMMPIMVEVVDESQPVIGGEDFHWATALVDAKGTLKLSPAA KKQGMPFNIMDGQLAVYSPNGTKKSCGHEPCEYLPVMMSGDAIMVTSSLVH Requirement: Original DNA code (itemize the steps you would take to get to know the original DNA code of Cytosine in focus)
What will be the overall anti-codon sequence in tRNA for this mRNA? 5’-GUAGCCUUAUCUAGCGAUCACCGUCCGUAUUACUAGUGGCCAGACUCUUUUCACCAUGUAUAGUUG-3’
Translate the following mRNA nucleotide sequence into an amino acid sequence, starting at the first base: 5’ - UGUCAUGCUCGUCUUGAAUCUUGUGAUGCUCGUUGGAUUAAUUGU - 3’
mRNA sequence of A gene If we have the following mutations, find the type of the mutation (silent or missense or nonsense?) 17CàU 36GàA 49GàU 115AàC 5’ AAACUGUGACUGAACCUCAAACCCCAAACCAGCCCGAGGAGAACCACAUUCUCCCAGGGA CCCAGGGCGGGCCGUGACCCCUGCGGCGGAGAAGCCUUGGAUAUUUCCACUUCAGAAGCC UACUGGGGAAGGCUGAGGGGUCCCAGCUCCCCACGCUGGCUGCUGUGCAGAUGCUGGACG ACAGAGCCAGGAGGGAGGCCGCCAAGAAGGAGAAGGUAGAGCAGAUCCUGGCAGAGUUCCAGC UGCAGGAGGAGGACCUGAAGAAGGUGAUGAGACGGAUGCAGAAGGAGAUGGACCGCGGCCUGA GGUAGAAGCCGCUGGGGCUUGGGGCU-3’
The following is as segment of mRNA: 5'-UCGGAAUGUGGUGGCAUACAGGCUUACAGAACUAAGUCUGAGAAU-3' A. How many amino acids long will be the protein translated from the only reading frame available in this segment? B. If a mutation changes the third letter of the stop codon in the only reading frame available in this segment, how many amino acids long will be the protein translated?
Below is the CODING sequence of a gene. An A is inserted at position 131. Insert the variant and write the mature mRNA sequence. Then write the amino acid sequence of the resulting transcript. AGAGCTACCAGCTTTAGCGGGATATAAACACACTTATCCTACTATCCCTA 51 TCTTCCCCCAAAGAGGGATCATGCCGTCGACGGCCAAACCGATCGAGCGG 101 AGGTTAAGGGCCATTGGAAAAGGACACTCTGTACGACTAAGAAAATAGC 151 AGCGACTGAGCTGAACGCTACGGGGGGGGGGGTATATACCCCCCCCCCCC 201 CCAGCTACGAGCGACTTTTTATTTTTTTTTTTTATTTTTTTTCTTTTTTA 251 TTTTTTTTGTTTTTTTTTTTCGCGACTACAGAGACTTCTAGCGATCGACG 301 AGCTAGCTAGCGCGGCATCGGACGCGATCGCGATCCTAGACTCTACGAT