What are the values of X[i] and X[i+1] after code corresponding to the following code is run? int X[5]; int i=0; int A = 100, B = 200, C = 300; X[i] = A; X[i+1] = B; C = X[i]; X[i] = X[i+1]; X[i+1]= C;
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- Write a java code for the following. Write two methods that return the union and intersection of two arrays of integers using the following header: public int [ ] union(int arr1[ ], int arr2[ ] ) public int [ ] intersection(int arr1[ ], int arr2[ ]) For example, the union of two array lists {2, 3, 1, 5} and {3, 4, 6} is {2, 3, 1, 5, 3, 4, 6} and intersection is {3}. Write a test program that prompts the user to enter two lists of size 4 each, and displays their union and intersection. The numbers are separated by exactly one space in the output.What is wrong with the following code? int *p;. //Line 1int *q;. //Line 2 p = new int [5];. //Line 3 *p = 2; //Line 4 for (int i = 1; i < 5; i++). //Line 5p[i] = p[i-1] + i;. //Line 6 q = p;. //Line 7 delete [] p; //Line 8 for (int j = 0; j < 5; j++) //Line 9 cout << q[j] << " "; //Line 10 cout << endl; //Line 11I am trying to write a code that swaps 1st element of an array with 2nd one, 3rd with 4th and keeps like that. It is not working and instead I wrote a code that is reversing the order. (better explanation on pictures attached.) I am using Java. public static void swapPairs(String[]array) {for(int i= 0; i< array.length / 2; i++) {int j= array.length - i -1;swap(array, i, j);}}public static void swap(String[] array, int i, int j) {String temp= array[i];array[i]= array[j];array[j]= temp;}
- Use Java programming. Write the removeEvens() method, which receives an array of integers as a parameter and returns a new array of integers containing only the odd numbers from the original array. The main program outputs values of the returned array. Hint: If the original array has even numbers, then the new array will be smaller in length than the original array and should have no blank elements. Ex: If the array passed to the removeEvens() method is [1, 2, 3, 4, 5, 6, 7, 8, 9], then the method returns and the program output is: [1, 3, 5, 7, 9] Ex: If the array passed to the removeEvens() method is [1, 9, 3], then the method returns and the program output is: [1, 9, 3] import java.util.Arrays; public class LabProgram { public static int[] removeEvens(int [] nums) { /* Type your code here */} public static void main(String[] args) { int [] input = {1,2,3,4,5,6,7,8,9};int [] result = removeEvens(input); // Helper method Arrays.toString() converts int[] to a…Consider the following array: int[] a = { 1, 2, 3, 4, 5, 4, 3, 2, 1, 0 };What are the contents of the array a after the following loops complete?a. for (int i = 1; i < 10; i++) { a[i] = a[i - 1]; } b. for (int i = 9; i > 0; i--) { a[i] = a[i - 1]; }c. for (int i = 0; i < 9; i++) { a[i] = a[i + 1]; }d. for (int i = 8; i >= 0; i--) { a[i] = a[i + 1]; }e. for (int i = 1; i < 10; i++) { a[i] = a[i] + a[i - 1]; }f. for (int i = 1; i < 10; i = i + 2) { a[i] = 0; }g. for (int i = 0; i < 5; i++) { a[i + 5] = a[i]; }h. for (int i = 1; i < 5; i++) { a[i] = a[9 - i]; }In java: Write a program using a Scanner that asks the user for a number n between 1 and 9 (inclusive). The program prints a triangle with 2n - 1 rows. The first row contains only the square of 1, and it is right-justified. The second row contains the square of 2 followed by the square of 1, and is right justified. Subsequent rows include the squares of 3, 2, and 1, and then 4, 3, 2 and 1, and so forth until n rows are printed. Starting at row n + 1, the squares between (n - 1) to 1 are printed, again right justified. Row n + 2 prints the squares between (n -2) to 1. Notes Your solution should NOT use the conditionaloperator Your solution should NOT use tabs Your solutions SHOULD have at least one nested loop
- Explain this C code line per line please #include <stdio.h> #include <malloc.h> void printArray(int**, int); int main() { int i = 0, j = 0, n = 5; int **arr = (int**)malloc(n * sizeof(int*)); for(int i=0;i<n;i++){ *(arr+i) = (int*)malloc(n*sizeof(int)); } for(i=0;i<n;i++){ for(int j=0;j<n;j++){ *(*(arr+i) + j) = 0; } } printArray(arr, n); for(i=0;i<n;i++){ *( *(arr + i) + i) = i+1; } printArray(arr,n); return 0; } void printArray(int ** array, int size) { int i,j; for(i = 0;i<size;i++){ for(j=0;j<size;j++){ printf("%d ", *( *(array + i) + j)); } printf("\n"); } printf("\n"); }Write a program that reads a list of integers, and outputs those integers in reverse. The input begins with an integer indicating the number of integers that follow. For coding simplicity, follow each output integer by a space, including the last one. Assume that the list will always contain fewer than 20 integers. Ex: If the input is: 5 2 4 6 8 10 the output is: 10 8 6 4 2 To achieve the above, first read the integers into an array. Then output the array in reverse. import java.util.Scanner; public class LabProgram { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int[] userList = new int[20]; // List of numElement integers specified by the user int numElements; // Number of integers in user's list// Add more variables as needed numElements = scnr.nextInt(); // Input begins with number of integers that follow/* Type your code here. */}}Consider the following array: int a[ ] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0}; What are the contents of the array after the following loops complete? for (int i = 1; i < 10; i++) { a[i] = a[i– 1]; } for (int i = 9; i > 0; i--) { a[i] = a[i – 1]; } for (int i = 0; i < 9; i++) { a[i] = a[i + 1]; } for (int i = 8; i >= 0; i--) { a[i] = a[i + 1]; } for (int i = 1; i < 10; i++) { a[i] = a[i ] + a[i– 1]; } for (int i = 1; i < 10; i = i + 2) { a[i] = 0;} for (int i = 0; i < 5; i++) { a[i + 5] = a[i]; } for (int i = 1; i < 5; i++) { a[i] = a[9 - i]; } a[0] a[1] a[2] a[3] a[4] a[5] a[6] a[7] a[8] a[9] a b c d e f g h
- You are given two int variables j and k, an int array zipcodeList that has been declared and initialized, and a boolean variable duplicates. Write some code that assigns true to duplicates if any two elements in the array have the same value, and that assigns false to duplicates otherwise. Use only j, k, zipcodeList, and duplicates. this is a java programIn python, Problem Description:Sheldon and Leonard are physicists who are fixated on the BIG BANG theory. In order to exchange secret insights they have devised a code that encodes UPPERCASE words by shifting their letters forward. Shifting a letter by S positions means to go forward S letters in the alphabet. For example, shifting B by S = 3 positions gives E. However, sometimes this makes us go past Z, the last letter of the alphabet. Whenever this happens we wrap around, treating A as the letter that follows Z. For example, shifting Z by S = 2 positions gives B. Sheldon and Leonard’s code depends on a parameter K and also varies depending on the position of each letter in the word. For the letter at position P, they use the shift value of S = 3P + K. For example, here is how ZOOM is encoded when K = 3. The first letter Z has a shift valueof S = 3 × 1 + 3 = 6; it wraps around and becomes the letter F. The second letter, O, hasS = 3 × 2 + 3 = 9 and becomes X. The last two letters…I have a java program that is supposed to compare the sums of the columns of a 2D array and output the index of the column with the largest sum. I was able to find the column sums but I do not know how to compare the different sums and output the index of the largest sum. Here is the piece of code that finds the column sums: int [] colSum = new int [arr[0].length]; for (int k = 0; k < colSum.length; k++) { System.out.print(colSum[k]); ----> colSum[k] = the column sums How do I compare the integers in colSum[k] to find the largest sum and how do I output the index of the largest sum?
