What is the angle of twist for the aluminum bar shown? The shear modulus of elasticity, G= 3.7 x 10° psi
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Q: B A 105 90 30 C -30° 75 300 lb 400 lb
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- A steel bar, whose cross section is 0.60 inch by 4.10 inches, was tested in tension. An axial load of P = 31,025 lb. produced a deformation of 0.115 inch over a gauge length of 2.10 inches and a decrease of 0.0080 inch in the 0.60-inch thickness of the bar. a. Determine the lateral strain. b. Determine the axial strain. c. Determine the Poisson’s ratio v. d. Determine the decrease in the 4.05-in. cross-sectional dimension (in inches).Compute the value the shear modulus G of steel whose modulus of elasticity E is 200 GPa and poisson's ratio is 0.30.The compound bar ABCD has a uniform cross-sectional area of 0.25 in.² When the axial force P is applied, the length of the bar is reduced by 0.018 in. Determine the magnitude of the force P. The moduli of elasticity are 29 x 10^6 psi for steel and 10 x 10^6 psi for aluminum. Please include the details. Thank you.
- The strain in member AB was measured to be 9 × 10^−4. If the member is an ? 3 × 3 × 1/4 of A36 steel (refer to AISC Table 1-7, next page), determine thefollowing:a. What is the change in length in inches?b. What is the force in the member?Note: For all structural steels: modulus of elasticity, ? = 29,000 ksiQ#5: The cross section of a wood beam carries a bending moment M of magnitude 20R lb.-in. acting at 10⁰ to the horizontal. Determine(a)the angle between the neutral axis and the horizontal; and (b) the maximum bending stress acting on the cross section. Note : Use R=980 For Details See Picture AttachedThe figure shows a glued joint, known as a finger joint, in a 200 mm. by 25 mm piece of lumber. Find the normal and shear stresses acting on the surface of the joint.
- determine the tensile stress in each segment of the bar shown. Segment AB cross section 2in x 2in. Segment BC has a circular cross-section with a diameter of 1.75 in . The tensile load P= 75 kipsThe bronze bar 3 m long with a cross-sectional area of 350 mm2 is placed between two rigid walls. At a temperature of –20°C, there is a gap of 2.2 mm, as shown below. Determine the temperature in °F at which the compressive stress in the bar will be 30 MPa. Use α =18(10)-6/°C and E = 80 GPa. Note: Draw the Free Body Diagram, include the units/dimensions, use the proper formula and round-off all the answers and final answers to 3 decimal places.UPVOTE will be given! Please write the solutions completely and legiby. Box the final answer. Answer in 3 decimal places! Strength of Materials The assembly shown is made up of T-shape steel and two wood as shown. A bending moment M is applied to the composite beam. Given: Es = 200 GPa Ew = 25 GPa M = 90 kN.M h = 200 mm c. Calculate the absolute maximum stress in the steel in MPa. d. Calculate the stress in the steel along the top edge in MPa.
- A 5 ft. long laminated wood beam is built up by gluing together three 2” x 6” boards to form asolid beam 6” x 6” cross section, as shown in the figure. Calculate the maximum allowable valueof P (lb.) such that both the (1) allowable shear stress in the glued joints of 100 psi and the (2)allowable bending stress of 1200 psi is not exceeded. (Disregard the weight of the beam).[Formula: Bending Stress: = (M)(y)/I; max = (M)(c)/I; Transverse Shear Stress: =(V)(Q)/(I*t); max = (V)(QNA)/(I*tNA)]Calculate the total deformation of steelbars shown in Figure. (d1=15 mm, d2=25 mm and E=210 GPa) A= 5, B=3, C=8A hollow steel member has an inside diameter of 50mm,a wall thickness of 5mm,a length of 1500mm and a modulus of elasticity of 210GPa.if the member is subjected to a tensile load of 5KN, determine each of the following dimensional changes.(take Poisson's ratio to be 0.4) 1.elongation 2.change in thickness