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- A quantity of 1.00 x 102 mL of 0.500 M HCl was mixed with 1.00 x 102 mL of 0.500 M NaOHin a constant pressure calorimeter of negligible heat capacity. The initial temperature of the HCLand NaOH solutions was same, 22.50 0C, and the final temperature of the mixed solution was25.86 0C. Calculate the (a) heat of the reaction at constant pressure (qp) and (b) the change inenthalpy for the neutralization reaction (ΔHrxn) in kJ per mole of HCl. Assume that the densitiesand specific heat of the solutions are the same as for water (1.00 g/mL and4.184 J/g.0C, respectively).NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)A pellet of benzoic acid standard was combusted in a bomb calorimeter to determine the experimental calorimeter constant. After 6 mins of monitoring the temperature, the bomb was fired. The following data were obtained. mole of benzoic acid: 0.0049 mol mass of burnt fuse wire: 0.0125 g qwire,surr: 5858 J/g ΔHcombustion of benzoic acid: -3228.0 kJ/mol Δng (combustion of benzoic acid): -0.5 mol R: 8.314 J/mol•K r1: 0ºC/min r2: 0ºC/min Tf: 30.4ºC Ti: 28.4ºC Determine the calorimeter constant (in J/ºC). Report your answer in 2 decimal places.What is the standard enthalpy of a reaction for w hichthe equilibrium constant is (a) doubled. (b) halved w hen thetemperature is increased by 10 Kat 298 K?
- Consider the following reaction: H2(g) + ½ O2 (g) ------> H2O (g) The standard enthalpy of formation of gaseous H2O at 298 K is -241.82 kJ mol-1. Calculate the value at 153 0C. Given Cp,m for H2O(g): 33.58 kJ mol-1; H2 (g): 28.84 kJ mol-1; O2 (g): 29.37 kJ mol-1. Assume heat capacities are independent of T. NOTE:answer in kilojoules per mole (kJ/mol)1 mol of toluene, at 1 atm is heated up from 25ºC to 35ºC. How much heat do we need for that? Which is the enthalpy change of the process? (use: (�H/�V)p. Assume the pressure does not change. Data: cp = 0.405 cal/(g º), ρ = 0.8669 g/cm3 eta =1.0 x 10-3 K-1.A student poured 100 ml of water (density = 1.00 g / mL) into a coffee calorimeter, noted that the temperature of the water was 18.8oC, then added 5.33 g KOH. With the lid on, the mixture was stirred, temperature increased and the maximum temperature reached at the time of mixing 31.6 oC. Calculate the heat of the system in this dissolution reaction (qsys). ( Approximate the specific heat capacity, cp as 4.18 J g-1 K-1. Do not consider the contribution to the heat generated from the calorimeter; assume that this is zero. Only calculate the heat from the heat capacity of the solution. make sure you consider the sign of qsys qsys for dissolution of KOH = J
- At constant pressure and 25C, what is enthalpy for the reaction: 2C2H6 + 7O2 -> 4CO2 + H2O, if the complete consumption of 12g of C2H6 liberates - 700kJ of heat energy? (-3508 kJ)Estimate reaction enthalpy and predict the sign of reaction entropy included attatchemnt of mecahnism and of original reactionA rigid insulated tank is divided into 2 equal compartments by athin rigid partition. One of the compartments contains air, assumedto be an ideal gas at 800 kPa and 250◦C. The other compartment isunder a vacuum. The partition is suddenly broken and the air rushesinto the evacuated compartment. The tank pressure and temperatureeventually equilibrate. (a) what is the final temperature of the gas ◦C?(b) what is the final pressure, kPa?(c) how much work is done by the system, kJ/kg?(d) how much heat is transferred to the system kJ/kg
- Gibbs free energy (G�) is a measure of the spontaneity of a chemical reaction. It is the chemical potential for a reaction, and is minimized at equilibrium. It is defined as G=H−TS�=�−�� where H� is enthalpy, T� is temperature, and S� is entropy. The chemical reaction that causes magnesium to corrode in air is given by 2Mg+O2→2MgO2Mg+O2→2MgO in which at 298 K, ΔH∘rxn = −1204 kJΔ�rxn∘ = −1204 kJ and ΔS∘rxn = −217.1 J/KΔ�rxn∘ = −217.1 J/K. Part A Part complete What is the standard Gibbs free energy for this reaction? Assume the commonly used standard reference temperature of 298 K. Part B What is the Gibbs free energy for this reaction at 5958 KK ? Assume that ΔHΔ� and ΔSΔ� do not change with temperature. Express your answer to two decimal places and include the appropriate units. Part C At what temperature Teq�eq do the forward and reverse corrosion reactions occur in equilibrium? Express your answer as an integer and include the appropriate units.Calculate the enthalpy change for the reaction C(s) + 2H2 (g)--->CH4(g) from the following data. C(s) + O2 (g) ---> CO2(g). ΔH = – 393.5 kJ/mol H2(g) + 0.5 O2 (g) ---> H2O(l). ΔH = – 285.8 kJ/mol CH4(g) + 2 O2 (g)---> CO2(g) + 2 H2O(l). ΔH = – 890.2 kJ/mol1. Calculate the standard enthalpy of formation of C10H10. Its standard enthalpy of combustion is shown by the equation: 2C10H10 (l) + 25O2 (g) → 20CO2 (g) + 10H2O (l) ∆H = 10,314 KJ/mol The standard heat of formation (KJ/mol) at 298.15oC : CO2 = -393.5 ; H2O(l) = -285.8 2. Determine ΔG° at 298.15K for the reaction: 4Fe (s) + 3O2 (g) → 2Fe2O3 (s) Given that ΔH° = -1648 kJ ; ΔS° = -549.3 J/K 3. In the picture, Find the the ∆H°rxn if ∆G°rxn is 420 kJ/mol and ∆S°rxn is -143 J/mol*k