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- OChem HELP... Draw the conformational structures (chair or boat conformations) for the MAJOR product formed when 1-tert-butylcyclohexene reacts with each of the following reagents. Also, indicate if the product obtained is racemic form. a) Br2, CCl4 b) Br2, H2O c) OsO4, then aqueous NaHSO3 d) ICl e) mCPBA, then H3O+, H20 f) O3, then Me2S (conformational structure not required) g) BH3:THF, then H2O2, HO- h) D2, Pt i) Hg(OAc)2 in THF-H2O, then NaBH4, HO- j) BD3 :THF, then CH3CO2TAs a rule, axial alcohols oxidize somewhat faster than equatorial alcohols. Which would you expect to oxidize faster, cis-4-tert-butylcyclo-hexanol or trans-4-tert-butylcyclohexanol? Draw the more stable chair conformation of each molecule.Draw structures corresponding to the following names: (a) 3, 3-Dimethyl-4-octyne (b) 3-Ethyl-5-methyl-1, 6, 8-decatriyne (c) 2, 2, 5, 5-Tetramethyl-3-hexyne (d) 3, 4-Dimethylcyclodecyne (e) 3, 5-Heptadien-1-yne (f) 3-Chloro-4, 4-dimethyl-1-nonen-6-yne (g) 3-sec-Butyl-1-heptyne (h) 5-tert-Buty1-2-methyl-3-octyne
- An IR spectra show C—H peaks in the functional group region at values 2990 and 2890 cm^-1, but does not show any C—H peaks above 3000 cm^-1. What can be concluded about this compound? This compound only contains H’s bonded to sp3 carbons. This compound only contains H’s bonded to sp2 carbons. This compound only contains H’s bonded to sp carbons. This compound only contains H’s bonded to sp and sp2 carbons.Compound A has the formula C5H10O that is produced by oxidation of a conpound that has the formula C5H12O. Compound A has an IT spectrum the has an absorbance at 1700 cm^-1 and no broad absorbance from 2500-3500 cm^-1. The 1H and 13C spectrums of Compound A both have 4 peaks. What is tbe structure of Compound A? Thank you for the help!OChem help with IUPAC names involving Ph and Bn The phenyl group (Ph-R, C6H5-R) can be formed by removing a hydrogen from benzene and attaching a substituent to where the hydrogen was removed. The benzyl group (abbv. Bn), similar to the phenyl group, is formed by manipulating the benzene ring. In the case of the benzyl group, it is formed by taking the phenyl group and adding a CH2 group to where the hydrogen was removed. Its molecular fragment can be written as C6H5CH2-R, PhCH2-R, or Bn-R. Please provide the IUPAC name for the following: (Ph)2CHC(CH3)2CC(CH2)3CH(Bn)CHO