What is the maximum amount of Al,Cl, that can be formed from the reaction of 4.0 mol of Al with 5.0 mol of Cl, according to this equation? 2 Al(s) +3 Cl2(g) > Al,Cl,(s) А. 9.0 mol В. 3.7 mol С. 2.0 mol D. 1.7 mol E. 5.2 mol

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40.
What is the maximum amount of Al,Cl, that can be formed from the reaction of 4.0 mol
of Al with 5.0 mol of Cl, according to this equation?
2 Al(s) + 3 Cl>(g) > Al,Cl6(s)
А.
9.0 mol
В.
3.7 mol
С.
2.0 mol
D.
1.7 mol
E.
5.2 mol
Transcribed Image Text:40. What is the maximum amount of Al,Cl, that can be formed from the reaction of 4.0 mol of Al with 5.0 mol of Cl, according to this equation? 2 Al(s) + 3 Cl>(g) > Al,Cl6(s) А. 9.0 mol В. 3.7 mol С. 2.0 mol D. 1.7 mol E. 5.2 mol
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This question is based on the concept of limiting reagent. Limiting reagent is the reactant that finishes off first in reaction and decides the yield of the product. Among both the reactants, whichever one will give the least yield of product will be our limiting reagent.

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