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- For the calculation of sd, shouldn't it be (0.97-1.09) and so on... because 0.97 = x and 1.09 = mean? and the formula for sd is squared of the summation of (x-mean)^2 divide by n?A chemist working in a hospital clinical laboratory obtained the following values for uric acid in blood serum: 4.63, 4.58, 4.82, 4.31, 4.67 and 4.60 mg%. What value should be reported as the mean? Value of QT at 90 % confidence level is 0.56.4. A fat sample with combination of acids contain standard hydrochloric acid for blank and sample with 8mL and 5mL respectively. The normality of the standard hydrochloric acid is 0.93N and the weight of the sample is 3 grams. Calculate the saponification value.
- An analysis of city drinking water for total hardness was done by two students in the laboratory and produced the following results (in ppm CaCO3): Student A: 228.3, 226.4, 226.9, 227.1, and 228.6. Student B: 229.5, 226.1, 230.7, 223.8, and 227.5What is the 95% confidence interval for the mean?what is meant by the term gravimetric factorFor the standard equation, shouldn't it be (0.97-1.09) and so on... because (x-mean)
- The gravimetric factor used to express CoCBr6·H20 in a sample that is finally weighed as PbClBr is choose below: FW PbClBr / 6 x FW CoCBr6·H20 FW CoCBr6·H20 / FW PbClBr FW CoCBr6·H20 / 6 x FW PbClBr 6 x FW PbClBr / FW CoCBr6·H20To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations are different. Location 1 standard deviation: 0.050 Location 2 standard deviation: 0.34 What is the calculated ? value for comparing the standard deviations?The inital points are ( 0, 27.12) and (0.00250 , 5.17)
- To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations are different. Location 1 Standard deviation = 0.050 Location 2 standard deviation = 0.34 a) What is the calculated ? value for comparing the standard deviations? Fcalc = __________________For the following data, calculate mean, deviation, standard deviation, median, variance and range ( 14.2273, 14.2301, 14.2272, 14.2296, 14.2287 *The analysis shows different concentrations based on replicate determinations of Zn in a water sample: 0.754 mg, 0.721 mg, 0.734 mg, 0.731 mg and 0.742 mg. What is the absolute error if the standard solution has 0.750 mg of Zn?