What is the molarity (M) of a solution containing 72.3 grams of potassium nitrate (MM = 101.11 g/mol) in a total volume of 750.0 mL? Group of answer choices 0.953 M 9.53 x 10E(-3) 9.53 x 10E(-4) 9.53 x 10E(-2)

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Q: What is the concentration of your stock solution in mM?

A: 1% means 1/100 So, 0.1% = 0.1/100 Thus, 0.1% = 0.1 ug / 100 mL = 0.001 ug/mL

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A: Step : 1               Calculate the molarity of each solution.

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