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- Sample Relative Concentration of Tea Extracts % Inhibition Green Tea ( 0.25 mg ) 0.25 0.974 Green Tea ( 0.5 mg ) 0.5 0.967 Green Tea ( 0.75 mg ) 0.75 0.965 Green Tea ( 1.5 mg ) 1.5 0.959 Back tea ( 0.25 mg ) 0.25 0.858 Black tea ( 0.5 mg ) 0.5 0.976 Back tea ( 0.75 mg ) 0.75 0.982 Black tea ( 1.5 mg ) 1.5 0.969 plot the graphIf you need 2.5 mg/liter, 2,4-D in 1 liter of medium and the stock solution of 2,4-D contains 10 mg/100 ml, how much stock solution do you need? why BAP is preferred over other cytokinin during commercial plant tissue cultureShow the calculations required to make up 250mlof a stock solution of this chemical that will then be at the working concentration when 1 volume of this solution is added to 10 volumes of cell culture medium.
- A bacterial culture is grown using either octadecane (C18H38) or pentachlorophenol (C6HOCl5)) as the sole source of carbon and energy. The cell yield value is determined by dry weight analysis to be 1.49 for octadecane and 0.05 for pentachlorophenol. Using either octadecane or pentachlorophenol, please describe the steps taken (and the final result) showing what percentage of the substrate carbon will be found as cell mass and as CO2? Please show all calculations.A bacterial culture is grown using either octadecane (C18H38) or pentachlorophenol (C6HOCl5)) as the sole source of carbon and energy. The cell yield value is determined by dry weight analysis to be 1.49 for octadecane and 0.05 for pentachlorophenol. Using either octadecane or pentachlorophenol, please describe the steps taken (and the final result) showing what percentage of the substrate carbon will be found as cell mass and as CO2? Please show all calculations and give correct answers.A bacterial culture is grown using either octadecane (C18H38) or pentachlorophenol (C6HOCl5)) as the sole source of carbon and energy. The cell yield value is determined by dry weight analysis to be 1.49 for octadecane and 0.05 for pentachlorophenol. Using either octadecane or pentachlorophenol, please describe the steps taken (and the final result) showing what percentage of the substrate carbon will be found as cell mass and as CO2? Please show all calculations and give correct answers. Please answer the question.
- Manufacture single cell protein(SCP) animal feed from cassava effluent (mainly starch). The effluent is obtained from pressing of crushed fresh cassava pulp generated by gari processing factory. Using Saccharomyces cerevisiae strain; (a) Select and describe fermentation process for the SCP production stating the conditions involved (b) State the monitory measures you would consider for the yield of production (c) State how the product can be verified for animal feedingBefore a sugar can be analyzed by gas chromatography(GLC) or GLC/MS, it must be converted to a volatile derivative. Why can’t sugars be analyzed directly?Relative Concentration of Tea Extracts % Inhibition 0.25 0.974 0.5 0.967 0.75 0.965 1.5 0.959 0.25 0.858 0.5 0.976 0.75 0.982 1.5 0.969 0.25 0.974 plot the graph
- produce single cell protein(SCP) animal feed from cassava effluent (mainly starch). The effluent is obtained from pressing of crushed fresh cassava pulp generated by gari processing factory. Using Saccharomyces cerevisiae strain; (a) Select and describe fermentation process for the SCP production stating the conditions involved (b) State the monitory measures you would consider for the yield of production (c) State how the product can be verified for animal feedingIn a photosynthetic investigation, a student measured the following pH of the stroma and the inner thylakoid compartments of spinach leaf cells at the conclusion of the experiment. Source of Fluid pH (mean) Standard Error of Mean (SEM) Stroma 8.2 0.75 Inner compartment of thylakoid 5.6 0.35 b. Construct an appropriately labeled graph to illustrate the sample means of the two locations to within 95% confidence (i.e. sample mean + 2 SEM).after a 5 g onion sample is divided into two equal parts, heat treatment to one of these partsit is being implemented. Then both heat-treated and non-treated parts are 10 times their weightit is ground in an environment containing as much buffer and the determination of pyruvate in the supernatants obtainedit's being done.a) As a result of measurements taken at 520 nm; absorbance value for the heat-treated sample;it was found that the absorbance value in the sample that was not heat treated was 0.123 and the absorbance value in the sample that was not heat treated was 0.520.The equation of the calibration accuracy for pyruvate is that y = 0.1367x – 0.001 (nmol/mL)according to the onion sample; a) independent of alinase activity; b) dependent on alinase activityand c) calculate the total pyruvate amounts in terms of nmol/g of onion.b) How is there a relationship between the activity of the enzyme allinase in onions and the amount of pyruvate?Dec,please explain.