What value is stored in 0x10000008 on a MIPS (big-endian) machine? Q2: What value is stored in 0x10000008 on a RISC-V (little-endian) machine?
Q: ermine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es. If…
A: It is defined as the method to specify the operand of an instruction. The job of a microprocessor is…
Q: Translate the following pseudo code to MIPS code: A-B-C Consider that the variables A, B, and C…
A: Answer:- (1)C codeA = B + CMIPS Codelw $t1, 0($s4) #$t1 = Blw $t2, 0($s5) #$t2 =…
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: The handwritten solution is given in the step-2.
Q: If R1=0x00009300 and R2=0x00009000, evaluate the following program and determine th content of…
A: Answer: Ro= 0x67983A5C This is given base address R1=…
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: your answer is given below:
Q: Q: Compute the physical address for the specified operand in each of the following instr The…
A:
Q: 4) Write an ALP for 8086 microprocessor to solve the following equation Y = (A x B) + C. A, B and C…
A: The 8086 code with comments is given in step 2.
Q: Consider the following register transfer statements for two 4-bit registers R1 and R2. xT: R1← R1+…
A: Given data Consider the following register transfer statements for two 4-bit registers R1 and R2.…
Q: Find the Addressing mode: Physical Address/es: Content of the destination:
A: Answers In the given instruction destination is EDX register and source data is the contents of…
Q: Find the physical memory address for each of the following logical memory addresses given by…
A: Find the physical memory address for each of the following logical memory addresses given by…
Q: Exercise 1: While Loop High-level code // determines the power of x such that 2x = 128 int pow = 1;…
A: Answer: I have given answer in the brief explanation.
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: Solution is given below-
Q: Suppose that DS-300H, SS=200H, CS=100H, CX=AF39H, ARRAY-=D3A4H, IP=5A76H, DI=245AH, SP=5489H,…
A:
Q: 2. Suppose we have two implementations of the same instruction set architecture. Computer A has a…
A: the answer is given below :
Q: 3.3 Consider a simple segmentation system that has the following segment table: Segment Starting…
A: Hey, since multiple sub parts questions posted, we will answer first three question according to our…
Q: Consider two different instruction sets, Il and 12. Il has 3 classes of instructions, A1, B1 and Cl…
A: The Answer is in Below Steps
Q: Problem 7 Assume that the LC-3 memory is set up in the following way. Memory Address X3FA0 X3FA1…
A: Het there, I am writing the required solution for the above stated question.
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: Here, I have to find addressing mode, physical address and content of the destination.
Q: Given x half Ox849a, Ox1234, Ox7cd3, O0000, and the base address of x is already stored in St3…
A:
Q: Given x: .half 0x849a, 0x1234, 0x7cd3, 0x0000, and the base address of x is already stored in $t3…
A: we use lh here for loading the bits and then use sh to store the value in $t1 register.
Q: Q2) Answer the following sentence with (True) or (False) and correct the false answer: (20 Marks) 1.…
A: Answer: 1.REPE, REPNZ. REPZ are usd for string operations likeCMPS , Movs. Hence it is true. 2.…
Q: 3. Translate the following C code to MIPS assembly code. Try to use a minimum number of…
A: The given code is: i $s0- j $s1- base of A[] $s2- base of B[] $s3 3.1. if (i == j)i += 2;elsej--;j…
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: The answer as follows
Q: The unique addresses assigned to the four registers (R11,R12,13,R14) of the I/O interface are equal…
A: When we connect the two capacitors,then assume the final voltage be V. The capacity of capacitor is…
Q: The 8-bit registers R1, R2, R3, and R4 initially have the following values: R1 - 1111 0010, R2- 1 1…
A:
Q: Assume that you are given the following MIPS code fragment: Label01: instruction1 instruction2…
A: suppose that the first instruction is located 10000, then the value of offset field of the…
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: Given The answer is given below.
Q: Problem Question 03 (C03) [0.5 + 0.5 = 1]: Given below are the contents of several Intel 8086…
A: Here is the answer:-
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: given, the contents of the register SI=AECDH. convert, AECDH from hexadecimal to decimal. 160 * 13 +…
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: Given The answer is given below.
Q: Topic : Writing MIPS code. 1.Consider the equation and write MIPS code for it:…
A: $s0 = Base address of array A[] $s1 = Base address of array B[] $s2 = X Given, X=(A[3]+B[5]) -…
Q: Consider the expression (a-1)*(((btc)3) d). Let X be the minimum number of registers required by an…
A: The answer for value of X is
Q: Translate the following pseudo code to MIPS code: A-B C Consider that the variables A, B, and C…
A: (1)C codeA = B + CMIPS Codelw $t1, 0($s4) #$t1 = Blw $t2, 0($s5) #$t2 = Cadd…
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: your answer is given below:
Q: Suppose that DS=300H, SS=200H, CS=100H, CX=AF39H, ARRAY=D3A4H, IP=5A76H, DI=245AH, SP=5489H,…
A:
Q: Q2) Answer the following sentence with (True) or (False) and correct the false answer: 1. CMPS is…
A: Given:
Q: Consider the following C code: i-0; while(i<10) { if (i%2=0) {.…..} i = i++; } Assume both the…
A: It is defined as a powerful general-purpose programming language. It can be used to develop software…
Q: 1. Consider the following MIPS instruction sw $t0, 24($s1) Find out the type of instruction format…
A: MIPS Processor Architecture: It is still one of the most widely used CPU architectures today. It's…
Q: An 8-bit computer has a registers R0-R7. The content of register R3 is 20H and R4 is 40H.The…
A: An 8-bit unsigned number might be a spectrum: The maximum value an 8-bit number can encode is 255,…
Q: 1) Assume that we have 32 bit wide memory system that is byte addressable. For the purposes of this…
A: …
![Q: B2.JPG MOV SP,[BP+DI+ACBAH] ВJPG PHY. ADD| С6079H АСH C607AH BDH С607вн | СЕН C607CH| F1H C607DH 02H…A: We need to find required addresses for given assembly code.](/questions-and-answers/b2.jpg-mov-spbpdiacbah-vjpg-phy.-addor-s6079h-ash-c607ah-bdh-s607vn-or-sen-c607chor-f1h-c607dh-02h-c/d2194d0d-d943-4cd8-84e9-b380c338f2bd){kind=link}
Q: B2.JPG MOV SP,[BP+DI+ACBAH] ВJPG PHY. ADD| С6079H АСH C607AH BDH С607вн | СЕН C607CH| F1H C607DH 02H…
A: We need to find required addresses for given assembly code.
Q: b) Given that the crystal frequency of 8051 Microcontroller is 11.059 megahertz, and one machine…
A: crystal frequency is 11.059 MHZ
Q: Consider a simple segmentation system that has the following segment table: Starting Address Length…
A: Given, Segment table: Segment Number Starting Address Length (Bytes) 0 830 346 1 110 110 2…
Q: 8. Write assembly program to perform the addition of two 32 bits binary numbers 235DA7C0H and…
A: Answer is given below-
Q: 8. Write assembly program to perform the addition of two 32 bits binary numbers 235DA7C0H and…
A: In 1977, Intel designed an 8- bit microprocessor by using NM technology, which is called 8085…
Q: 10110; BR = 11100111; CR = 10110001; DR = 10111010 Determine the 8-bit values in each register after…
A: AR = AR + BR 11010110 + 11100111 = 0110111101 CR = CR AND DR 10110001 and 10111010…
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: Addressing mode , of physical address and content of destination: MOV[BX],BX copy BX contents to…
Q: Suppose pep/8 contains following four hexadecimal values: A= 19AC, X=FE20, Mem[OA3F]=FFOO,…
A: Before starting:A: 19ACX: FE20Mem[0A3F]: FF00Mem[0A41]: 103D
Q: 3.3 Consider a simple segmentation system that has the following segment table: Segment |Starting…
A: Given: A simple segmentation system with segment numbers, starting address, and the length of the…
Q: Translate the following C code into MIPS code. Here X and Y are stored in $s1 and $s2 registers…
A: I have converted the given program into MIPS and also explained it for better understanding
Computer Science
Consider the following code: lb x6, 3(x7) sd x6, 8(x7) Assume that the register x7 contains the address (>10000000 and the data at address (>10000000 is: 0x11223344CCDDEEFF, while the data at address (>10000008 is: 0xF1E2D3C4B5A69780. Q1: What value is stored in 0x10000008 on a MIPS (big-endian) machine? Q2: What value is stored in 0x10000008 on a RISC-V (little-endian) machine?
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- A(n) __________ is a storage location implemented in the CPU.C language please use both the array notation and the pointer notation(e.g., *(pioBase+0)) to access the registers (e.g., pioBase[0]) (a) Set a base address for a generic PIO at 0x10008000 called pioBase. Assume this is just an 8-bitPIO port.(b) Set all the odd-numbered pins of this GPIO to inputs. Leave the even-numbered pins as outputs.Assume the following values are stored at the indicated memory addresses and registers:Address Value Register Value0x200 0xFF %rax 0x2000x204 0xAA %rcx 0x10x208 0x11 %rdx 0x30x20C 0x13Fill in the following table showing the values for the indicated operands: Operand Valueaddq %rcx,(%rax) ------------------subq %rdx,4(%rax) -------------------imulq $16, (%rax,%rdx,4) --------------------incq 8(%rax) -------------------decq %rcx -------------------subq %rdx,%rax ---------------------xorq %rdx,%rdx --------------------sarq 3, %rdx --------------------notq %rdx -------------------
- 3) The 8-bit register AR, BR, CR, and DR initially have the following values: [5]AR = 11010110; BR = 11100111; CR = 10110001; DR = 10111010Determine the 8-bit values in each register after the execution of the following sequenceof microoperations.AR AR + BR Add BR + ARCR CR AND DR, BR BR + 1 AND DR to CR, Increment BRAR AR - CR Subtract CR from ARComputer Science Assembly language 218 Q18: Given the code fragment: lst dd 2, 3, 5, 7, 9 mov rsi, 4 mov eax, 1 mov rcx, 2 lp: add eax, dword [lst+rsi] add rsi, 4 loop lp mov ebx, dword [lst] What would be in the eax ebx registers after execution (in hex)? Note, must precede hex number with 0x.Complete the following table: MIPS Instruction op code rs rt rd shamt funct imm. /address Hexadecimal Representation add $t4, $s2, $s1 addi $s0, $t0, 123 lw $s6, -88($t7) Note: In MIPS register file, temporary registers $t0-$t7 have indices 8-15 (respec- tively). Also, the saved registers $s0-$s7 have indices 16-23 (respectively).
- Computer organization and assembly language Please help me with this. I have to write line by line what each line of codes does. CODE IS BELOW: .model small .386 .stack 100h .data msg1 db 13, 10, "Enter any number --> ", "$" msg2 db "Enter an operation +,- * or / --> ",13, 10, "$" msg3 db "The Operation is --> ", "$" msg4 db "The result is --> ", "$" By_base dd 21 by_10 dd 10 ; 32 bits variable with initial value = 10 sp_counter db 0 ; 8 bits variable with initial value of zero disp_number dd 0 ; 32 bits variable with initial value = 0 disp_number2 dd 0 disp_number3 dd 0 op_type db 0 last_key dd 0 ; 32 bits variable with initial value of zero remainder db 0 .code main proc mov ax,@data;set up datasegment movds,ax mov dx,offset msg1 call display_message callm_keyin calloperation mov dx,offset msg1 calldisplay_message callm_keyin cmpop_type, "+" jnz short skip_plus callop_plus skiP_plus: cmp op_type, "-" jnz short skip_minus callop_minus…MIPS Programming Assignment Part I Rewrite C statements int i = 11; int j = 10; int A[] = { 0x11, 0x22, 0x33 }; int B[] = { 0x0, 0x1, 0x2, 0x3, 0x4, 0x5, 0x6, 0x7, 0x8 }; B[ 8 ] = A[ i - j ]; in MIPS assembly. Assume that addresses of variables i, j, A, and B are loaded into the registers $s3, $s4, $s6, and $s7, respectively: .data i: .word 11 j: .word 10 A: .word 0x11, 0x22, 0x33 B: .word 0x0, 0x1, 0x2, 0x3, 0x4, 0x5, 0x6, 0x7, 0x8 .text la $s3, i # load address of i la $s4, j # load address of j la $s6, A # load address of A la $s7, B # load address of B When you finished programming, add a comment at the end of your code which specifies what value is assigned to the location of B[8] after the program executes. Part IIWrite MIPS Assembly program that allows the user to enter a string of text. Determine whether the entered string is a palindrome (a word or a phrase that reads the same backward as forward, like "kayak" and "level") and print the result on the screen.*ASSEMBLY LANGUAGE* A subtraction instruction takes two operands, subtracts the first from the second, and the result goes into the second. Write a 16-bit subtraction instruction, where... The first operand is stored at the memory address contained within the %edx register. (NOTE: To be clear, the %edx register contains the memory address OF the operand, not the operand itself! Recall the syntax of "indirect addressing," to use here.) The second operand -- also where the result shall be stored -- is stored directly in the 16-bit %bp register.
- To see each addressing mode, translate the following pseudocode into MIPS assembly. The variables x and y should be placed in data memory because they are static and volatile. You do not need to keep the variables in memory while utilising register direct access. main() { static volatile int miles = prompt("Enter the number of miles driven: "); static volatile int gallons = prompt("Enter the number of gallons used: "); static volatile int mpg = miles / gallons; output("Your mpg = " + mpg);}Use the register and memory values in the table below for this question. Assume a 32-bitmachine. Assume each of the following questions starts from the table values; that is, DO NOT use valuechanges from one question as propagating into future parts of the question.Register Value Memory LocationValueR1 12 12 16R2 16 16 20R3 20 20 24R4 24 24 28a) Give the values of R1, R2, and R3 after this instruction: add R1, R2, R3b) What values will be in R1 and R3 after this instruction is executed: lw R2, 8(R1)c) What values will be in R2 and R4 after this instruction is executed: addi R2, R4, #16Compare 0-, 1-, 2-, and 3-address machines by writing programs to computeX = (A x B + C) / (D − E × B)for each of the four machines. The instructions available for use are as follows: M is a 16-bit memory address, and X, Y, and Z are either 16-bit addresses or 4-bit registers. The0-address machine uses a stack, the 1-address machine uses an accumulator, and the other two have16 registers and instructions operating on all combinations of memory locations and registers. SUB X,Y subtracts Y from X and SUB X, Y, Z subtracts Z from Y and puts the result in X. With 8-bit opcodesand instruction lengths that are multiples of 4 bits, how many bits does each machine need to computeX?