Answered: When 1.74g of unknown sample was…

When 1.74g of unknown sample was treated with BaCl2 solution,2.399g of BaSO4 was obtained as product. The % of sulphate in the original sample is (S=32.06g/mol ,0=16g/mol, Ba 137.33g/mol) %3D

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter13: Titrations In Analytical Chemistry

Section: Chapter Questions

Problem 13.27QAP

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When 1.74g of unknown sample was treated with BaCl2 solution,2.399g of BaSO4 was
obtained as product. The % of sulphate in the original sample is
(S=32.06g/mol ,0=16g/mol, Ba 137.33g/mol)
%3D

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