When 16.3 g of an organic compound known to be 57.15% C, 4.8% H, and 38.06% O by mass is dissolved in 700.7 g of water, the freezing point is −0.343⁢ ∘C. The normal freezing point of water is 0⁢ ∘C. What is the molecular formula for the organic compound? Assume that the organic compound is a molecular solid and does not ionize in water. ?f values for various solvents are given in the colligative constants table

Chemistry
10th Edition
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Chapter17: Spontaneity, Entropy, And Free Energy
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Problem 128IP: Some nonelectrolyte solute (molar mass = 142 g/mol) was dissolved in 150. mL of a solvent (density =...
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When 16.3 g of an organic compound known to be 57.15% C, 4.8% H, and 38.06% O by mass is dissolved in 700.7 g of water, the freezing point is −0.343⁢ ∘C. The normal freezing point of water is 0⁢ ∘C. What is the molecular formula for the organic compound? Assume that the organic compound is a molecular solid and does not ionize in water. ?f values for various solvents are given in the colligative constants table.

Constants for freezing-point depression and boiling-point elevation calculations at 1 atm:
K
f value* Normal freezing K value Normal boiling
Solvent
Formula
(°C/ m )
point ( °C)
(°C/ m)
point ( °C)
water
H20
1.86
0.00
0.512
100.00
C 6 H 6
cyclohexane C 6 H 12
C2 H 6 0
benzene
5.12
5.49
2.53
80.1
20.8
6.59
2.92
80.7
ethanol
1.99
|-117.3
1.22
78.4
carbon
СС 4
29.8
-22.9
5.03
76.8
tetrachloride
camphor
С 10 Н 16 0 37.8
176
Transcribed Image Text:Constants for freezing-point depression and boiling-point elevation calculations at 1 atm: K f value* Normal freezing K value Normal boiling Solvent Formula (°C/ m ) point ( °C) (°C/ m) point ( °C) water H20 1.86 0.00 0.512 100.00 C 6 H 6 cyclohexane C 6 H 12 C2 H 6 0 benzene 5.12 5.49 2.53 80.1 20.8 6.59 2.92 80.7 ethanol 1.99 |-117.3 1.22 78.4 carbon СС 4 29.8 -22.9 5.03 76.8 tetrachloride camphor С 10 Н 16 0 37.8 176
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