A student dissolves 14.52 grams of aspirin, C9H8O4 (180.1 g/mol), in 156.5 grams of diethyl ether. Use the table of boiling and freezing point constants to answer the q Solvent Formula Kb (°C/m) Kf(°C/m) Water H20 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHC13 3.67 Benzene C6H6 2.53 5.12 Diethyl ether CH;CH2OCH2CH3 2.02 The molality of the solution is m. The boiling point of the solution is °C.
A student dissolves 14.52 grams of aspirin, C9H8O4 (180.1 g/mol), in 156.5 grams of diethyl ether. Use the table of boiling and freezing point constants to answer the q Solvent Formula Kb (°C/m) Kf(°C/m) Water H20 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHC13 3.67 Benzene C6H6 2.53 5.12 Diethyl ether CH;CH2OCH2CH3 2.02 The molality of the solution is m. The boiling point of the solution is °C.
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter13: The Chemistry Of Solutes And Solutions
Section: Chapter Questions
Problem 111QRT: The organic salt [(C4H9)4N][ClO4] consists of the ions (C4H9)4N+ and ClO4. The salt dissolves in...
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Boiling Point Elevation/Freezing Point Depression
T = m K
Where:
Kb and Kf depend only on the SOLVENT. Below are some common values. Use these values for the calculations that follow.
T = m K
Where:
| T | = T(solution) - T(pure solvent) * |
| m | = (# moles solute / Kg solvent) |
| Kb | = boiling point elevation constant. |
| Kf | = freezing point depression constant. |
Kb and Kf depend only on the SOLVENT. Below are some common values. Use these values for the calculations that follow.
| Solvent | Formula | Kb (°C / m) | Kf (°C / m) |
|---|---|---|---|
| Water | H2O | 0.512 | -1.86 |
| Ethanol | CH3CH2OH | 1.22 | -1.99 |
| Chloroform | CHCl3 | 3.67 | |
| Benzene | C6H6 | 2.53 | -5.12 |
| Diethyl ether | CH3CH2OCH2CH3 | 2.02 |
note that ΔT as defined above will be a negative number for freezing point depression. Therefore, Kf must also be given as a negative number.
Transcribed Image Text:The boiling point of diethyl ether, CH3CH2OCH2CH3, is 34.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in diethyl ether is aspirin.
A student dissolves 14.52 grams of aspirin, C9H304 (180.1 g/mol), in 156.5 grams of diethyl ether. Use the table of boiling and freezing point constants to answer the questions below.
Solvent
Formula
Kb (°C/m) Kf (°C/m)
Water
H20
0.512
1.86
Ethanol
CH3CH2OH
1.22
1.99
Chloroform
CHC13
3.67
Benzene
C6H6
2.53
5.12
Diethyl ether CH;CH2OCH2CH3
2.02
The molality of the solution is
m.
The boiling point of the solution is
°C.
Transcribed Image Text:The boiling point of diethyl ether CH3CH2OCH2CH3 is 34.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in diethyl ether is estrogen (estradiol).
How many grams of estrogen, C18H2402 (272.4 g/mol), must be dissolved in 250.0 grams of diethyl ether to raise the boiling point by 0.450 °C ? Refer to the table for the necessary boiling or freezing point constant.
Solvent
Formula
Kb (°C/m) Kf (°C/m)
Water
H20
0.512
1.86
Ethanol
CH3CH2OH
1.22
1.99
Chloroform
CHC13
3.67
Benzene
C6H6
2.53
5.12
Diethyl ether CH3CH2OCH2CH3
2.02
g estrogen.
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