Which one of the following synthetic routes gives the best yield of meta-bromoanilinestarting with benzene?NH2HNO,1) Sn. HCIBr,A.FeBr,H,SO,2) NaOHBrmetabromoaniline1) Sn, HCIBr,HNO,В.H,SO,2) NaOHFeBr,HNO,Br,1) Sn, HCIC.FeBrH,SO,2) NaOH1) Sn, HCIHNOBr,D.2) NaOHHSOFeBr,O AO BO COuestion 146 ptsMacBook ProSearch or type URL

Benzene is an organic compound with the molecular formula C6H6. Benzene possesses 3 carbon-carbon…

Answered: Which one of the following synthetic…

Which one of the following synthetic routes gives the best yield of meta-bromoaniline starting with benzene? NH2 Br HNO 1) Sn, HCI A. FeBr, H,SO, 2) NaOH Br metabromoaniline HNO. 1) Sn. HCI Br.

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter19: Enolate Anions And Enamines

Section: Chapter Questions

Problem 19.55P

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Concept explainers

Alkanes and Cycloalkanes

Alkanes are saturated organic compounds which are made up of C and H atoms. Alkanes have the general formula of CnH2n+2. Alkane contains sp3 hybridized carbon atoms with four sigmas (σ) bonds & every hydrogen atom is connected with one of the carbon atoms. The size of the alkane could be determined by the number of carbon atoms located in it.

Question

Which one of the following synthetic routes gives the best yield of meta-bromoaniline
starting with benzene?
NH2
HNO,
1) Sn. HCI
Br,
A.
FeBr,
H,SO,
2) NaOH
Br
metabromoaniline
1) Sn, HCI
Br,
HNO,
В.
H,SO,
2) NaOH
FeBr,
HNO,
Br,
1) Sn, HCI
C.
FeBr
H,SO,
2) NaOH
1) Sn, HCI
HNO
Br,
D.
2) NaOH
HSO
FeBr,
O A
O B
O C
Ouestion 14
6 pts
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