Question
Asked Sep 13, 2019

While heating two different samples of water at sea level, one boils at 102°C and one boils at 99.2°C. Calculate the percent error for each sample from the theoretical 100.0°C.

check_circleExpert Solution
Step 1

The normal boiling point of water is 100 oC, so this can be taken as true value or accepted value.

The obtained values are 102 oC and 99.2 oC.

The percent error is given as:

True value - obtainedvalue100
Percent error
true value
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True value - obtainedvalue100 Percent error true value

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Step 2

Positive value of the difference only is taken.

The percent error when the boiling point is 102 oC is:

Percent errorTrue value-obtainedvalue x100
true value
Percent error100.0 °C-102.0°C x100=2.0%
100.0 C
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Percent errorTrue value-obtainedvalue x100 true value Percent error100.0 °C-102.0°C x100=2.0% 100.0 C

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Step 3

The percent error when the boiling po...

Percent errorTrue value-obtainedvalue x100
true value
Percent error100.0 °C-99.2°C |x100= 0.8%
100.0 C
help_outline

Image Transcriptionclose

Percent errorTrue value-obtainedvalue x100 true value Percent error100.0 °C-99.2°C |x100= 0.8% 100.0 C

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