Write a C code for the structure types of a dynamic linked list implementation of  a stack. Each node of the stack will have the following members:  Name: char type array  ID: integer type number  Grade: double type number  Link: pointer/link to next node Write functions to add and remove the nodes of the stack and use printf() to show  that the code is working properly.

5. fast please  Convert the following infix expression into its prefix and postfix equivalents: a / b - (c + d * e) / f * g For any postfix, show the final transformed expression using the stack method for transformation as explained in class showing all the relevant steps. For the prefix, show any needed reversion and the final transformed expression using the stack method for transformation as explained in class showing all the relevant steps. Draw and sequence your diagrams clearly

given code lab4   #include <stdio.h>#include <stdlib.h> /* typical C boolean set-up */#define TRUE 1#define FALSE 0 typedef struct StackStruct{int* darr; /* pointer to dynamic array */int size; /* amount of space allocated */int inUse; /* top of stack indicator - counts how many values are on the stack */} Stack; void init (Stack* s){s->size = 2;s->darr = (int*) malloc ( sizeof (int) * s->size );s->inUse = 0;} void push (Stack* s, int val){/* QUESTION 7 *//* check if enough space currently on stack and grow if needed */ /* add val onto stack */s->darr[s->inUse] = val;s->inUse = s->inUse + 1;} int isEmpty (Stack* s){if ( s->inUse == 0)return TRUE;elsereturn FALSE;} int top (Stack* s){return ( s->darr[s->inUse-1] );} /* QUESTION 9.1 */void pop (Stack* s){if (isEmpty(s) == FALSE)s->inUse = s->inUse - 1;} void reset (Stack* s){/* Question 10: how to make the stack empty? */ } int main (int argc, char** argv){Stack st1; init (&st1);…

Write a C code that will search an int type target from a dynamic linked list. The linked list contains int type values inside each of the nodes. The “search” function will use following input-output arguments,Input: Pointer to the head of the list that you are searching Target value that you are searchingOutput: Pointer to the node that contains the target if found or, NULL if not found.

Assume class StackType has been defined to implement a stack data structure as discussed in your textbook (you may also use the stack data structure defined in the C++ STL). Write a function that takes a string parameter and determines whether the string contains balanced parentheses. That is, for each left parenthesis (if there is any) there is exactly one matching right parenthesis later in the string and every right parenthesis is preceded by exactly one matching left parenthesis earlier in the string. e.g. abc(c(x)d(e))jh is balanced whereas abc)cd(e)(jh is not. The function algorithm must use a stack data structure to determine whether the string parameter satisfies the condition described above. Edit Format Table 12pt v Paragraph v |BIU A v ev T? WP O words ....

C++ ProgrammingActivity: Linked List Stack and BracketsExplain the flow of the main code not necessarily every line, as long as you explain what the important parts of the code do. The code is already correct, just explain the flow SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS int main(int argc, char** argv) {     SLLStack* stack = new SLLStack();     int test;     int length;     string str;     char top;     bool flag = true;     cin >> test;     switch (test) {         case 0:             getline(cin, str);              length = str.length();              for(int i = 0; i < length; i++){                 if(str[i] == '{' || str[i] == '(' || str[i] == '['){                     stack->push(str[i]);                 } else if (str[i] == '}' || str[i] == ')' || str[i] == ']'){                     if(!stack->isEmpty()){                         top = stack->top();                         if(top == '{' && str[i] == '}' || top == '(' && str[i] == ')' ||…

Data Structure Using C++  I need a function like this ::: float postfixEval(string postfix) {int a, b;stack<float> stk;string::iterator it;for(it=postfix.begin(); it!=postfix.end(); it++) {//read elements and perform postfix evaluationif(isOperator(*it) != -1) {a = stk.top();stk.pop();b = stk.top();stk.pop();stk.push(operation(a, b, *it));}else if(isOperand(*it) > 0) {stk.push(checkNumber(*it));}}return stk.top();} to evaluate postfix with more one digit in expression (multi digits) please just this function simple like the above