Write a function 1ink_to_list that takes in a linked list and returns the sequence as a Python list. You may assume that the input list is shallow; none of the elements is another linked list. Try to find both an iterative and recursive solution for this problem! def link_to_list(link): """Takes a linked list and returns a Python list with the same elements. >>> link Link(1, Link (2, Link(3, Link(4)))) >>> link_to_list(link) [1, 2, 3, 4] >>> link_to_list (Link.empty) [] пин "*** YOUR CODE HERE ***"

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