Write a function called printRange () that accepts two integers as arguments and prints the sequence of numbers between the two arguments, surrounded by brackets ([ ]) and separated by a comma and a space. Print an increasing sequence if the first argument is smaller than the second; otherwise, print a decreasing sequence. If the two numbers are the same, that number should be printed by itself. Here are some sample calls to printRange: printRange (2, 7) printRange(19, 11)-> [19, 18, 17, 16, 15, 14, 13, 12, 11] printRange(5, 5) -> [2, 3, 4, 5, 6, 7] -> [5] pr.cpp 1 #include using namespace std; 3 #include "pr.h" 4 pr.h 1. /** 2 efile pr.h 3 @author @version CS 150 Spring 2021 5 */ 4

I want the solution in C++ language i want the solution related to chapter 4 in the 10th edition of the textbook Solving the problems with C++. Also i want the solution that setups the midnight time to 0, and lists all the scenarios (possibilities) from that time and future time within 24 hrs.   4.7: Time Machine Your time machine is capable of going forward in time up to 24 hours. The machine is configured to jump ahead in minutes. To enter the proper number of minutes into your machine, you would like a program that can take a start time (in hours, minutes, and a Boolean indicating AM or PM) and a future time (in hours, minutes, and a Boolean indicating AM or PM) and calculate the difference in minutes between the start and future time. A time is specified in your program with three variables: int hours, minutes; bool isAM; // You can also use a char, i.e. A or P for example, to represent 11:50 PM, you would store: hours = 11,minutes = 50, isAM = false or if using a char, hours =…