Write a function that takes the first Node in a linked list as argument and (destructively) reverses the list, returning the first Node in the result.

What does the following function do for a given Linked List with first node as head? void fun1(struct node* head) { if(head == NULL) return; fun1(head->next); printf("%d ", head->data); } a) Prints all nodes of linked listsb) Prints all nodes of linked list in reverse orderc) Prints alternate nodes of Linked Listd) Prints alternate nodes in reverse order

You may do this assignment using either Java or C++. Do *not use the JDK LinkedList class or any linked list library! A linked list consists of zero or more nodes, which each contain one item of data and a link (Java reference, C++ pointer or reference) to the next node, if there is one. Linked List code is usually generic, so that you can use it to create a list of Strings, Students, Doubles, etc. For this assignment, you will write a simplified version of linked list that only can be used to create and use a list of ints and that has only a few of the functions typical of linked lists. The data element can be just an int, and the data type of the link to the next node can be just Node. You will need a reference (Java) or either a reference or a pointer (C++) to the first node, as well as one to the last node. Write a method/function that takes an in, creates a node with that int as its data value, and adds the node to the end of the list. This function will need to update the…

struct insert_at_back_of_sll { // Function takes a constant Book as a parameter, inserts that book at the // back of a singly linked list, and returns nothing. void operator()(const Book& book) { /// TO-DO (3) /// // Write the lines of code to insert "book" at the back of "my_sll". Since // the SLL has no size() function and no tail pointer, you must walk the // list looking for the last node. // // HINT: Do not attempt to insert after "my_sll.end()". // ///// END-T0-DO (3) ||||// } std::forward_list& my_sll; };