Write a function that will accept a dictionary as the input parameter and return a new dictionary where all of the key-value pairs are reversed. For example, if I pass in {"one": 1, "two": 2, "three":3}` I would be returned a dictionary that looked like '{"three": 3, "two":2, "one": 1}
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- Write a function piggyBank in Python that accepts a sequence of "coins" and returns counts of the coins and the total value of the bank. the coins will be given by a list of single characters, each one of 'Q','D','N',P', representing quarter, dime, nickel, penny the function returns a tuple with two items:1. a dictionary with counts of each denomination. They should always be listed in theorder 'Q','D','N',P'2. the total value in whole cents of the amount in the bank Sample result examples: >>> piggyBank(['D', 'P', 'Q', 'Q', 'D', 'P', 'P'])({'Q': 2, 'D': 2, 'N': 0, 'P': 3}, 73) >>> piggyBank(['D', 'D', 'N', 'N', 'N'])({'Q': 0, 'D': 2, 'N': 3, 'P': 0}, 35) >>> piggyBank(['P', 'D', 'N', 'P', 'N', 'N', 'N', 'Q', 'D', 'P', 'Q', 'Q', 'D'])({'Q': 3, 'D': 3, 'N': 4, 'P': 3}, 128) >>> piggyBank(['D', 'P', 'Q', 'Q', 'D', 'P', 'P'])==({'Q': 2, 'D': 2, 'N': 0,'P': 3}, 73)True Please only give to me the final code or "tool" that could generate any of the…Write a function in python, cannot use isalpha or .get named count_letters that takes as a parameter a string and returns a dictionary that tabulates how many of each letter is in that string. The string can contain characters other than letters, but only the letters should be counted. The string could even be the empty string (just ""). Lower-case and upper-case versions of a letter should be part of the same count. The keys of the dictionary should be upper-case letters. If a letter does not appear in the string, then it would not get added to the dictionary. For example, if the string is "AaBb" then the dictionary that is returned should contain these key-value pairs: {'A': 2, 'B': 2}Write a program that reads words passing from a string parameter and create a dictionary mapping last letters to the number of words ending with that letter. For example, the string is 'apple banana orange grape cherry', the program will out put a dictionary fruitName that print(fruitName) will give us output {'e': 3, 'a': 1, 'y': 1} def count_last_letter(words): # YOUR CODE HERE raise NotImplementedError()
- Write a python program... Write a function called safeAdd(d, k, v, unsafe=False) that takes either three or four input parameters when called. Here, d is a dictionary, k is a key and v is a value. The function will add the key:value pair k:v to the dictionary d if the key k is NOT in the dictionary.If the key is in the dictionary, the function will display the current value for that key, the new value you passed into the function and ask the user if they wish to proceed and overwrite the existing value.If the optional fourth parameter is True, then just add the key:value pair without checking if the key is already present.Sample run (user input is highlighted) >>> d = {'A':1}>>> safeAdd(d, 'B', 3}>>> display(d)A, 1B, 3>>> safeAdd(d, 'B', 2)The key B is already in the dictionary.Current value is 3. Do you want to replace this value with 2? [yes/no] yes>>> display(d)A, 1B, 2>>> safeAdd(d, 'A', 12)The key A is already in the…Write a function named count_letters that takes as a parameter a string and returns a dictionary that tabulates how many of each letter is in that string. The string can contain characters other than letters, but only the letters should be counted. The string could even be the empty string (just ""). Lower-case and upper-case versions of a letter should be part of the same count. The keys of the dictionary should be upper-case letters. If a letter does not appear in the string, then it would not get added to the dictionary. For example, if the string is "AaBb" then the dictionary that is returned should contain these key-value pairs: {'A': 2, 'B': 2} And no, we haven't covered the isalpha() funciton or the .get function, so don't use it.Implement the build_dictionary() function to build a word frequency dictionary from a list of words. Ex: If the words list is: ["hey", "hi", "Mark", "hi", "mark"] the dictionary returned from calling build_dictionary(words) is: {'hey': 1, 'hi': 2, 'Mark': 1, 'mark': 1} Ex: If the words list is: ["zyBooks", "now", "zyBooks", "later", "zyBooks", "forever"] the dictionary returned from calling build_dictionary(words) is: {'zyBooks': 3, 'now': 1, 'later': 1, 'forever': 1} The main code builds the word list from an input string, calls build_dictionary() to build the dictionary, and displays the dictionary sorted by key value. Ex: If the input is: hey hi Mark hi mark the output is: Mark: 1 hey: 1 hi: 2 mark: 1
- Implement the build_dictionary() function to build a word frequency dictionary from a list of words. Ex: If the words list is: ["hey", "hi", "Mark", "hi", "mark"] the dictionary returned from calling build_dictionary(words) is: {'hey': 1, 'hi': 2, 'Mark': 1, 'mark': 1} Ex: If the words list is: ["zyBooks", "now", "zyBooks", "later", "zyBooks", "forever"] the dictionary returned from calling build_dictionary(words) is: {'zyBooks': 3, 'now': 1, 'later': 1, 'forever': 1} The main code builds the word list from an input string, calls build_dictionary() to build the dictionary, and displays the dictionary sorted by key value. Ex: If the input is: hey hi Mark hi mark the output is: Mark: 1 hey: 1 hi: 2 mark: 1 CODE I HAVE TO USE: # The words parameter is a list of strings.def build_dictionary(words): # The frequencies dictionary will be built with your code below. # Each key is a word string and the corresponding value is an integer # indicating that word's frequency.…Implement the build_dictionary() function to build a word frequency dictionary from a list of words. Ex: If the words list is: ["hey", "hi", "Mark", "hi", "mark"] the dictionary returned from calling build_dictionary(words) is: {'hey': 1, 'hi': 2, 'Mark': 1, 'mark': 1} Ex: If the words list is: ["zyBooks", "now", "zyBooks", "later", "zyBooks", "forever"] the dictionary returned from calling build_dictionary(words) is: {'zyBooks': 3, 'now': 1, 'later': 1, 'forever': 1} The main code builds the word list from an input string, calls build_dictionary() to build the dictionary, and displays the dictionary sorted by key value. Ex: If the input is: hey hi Mark hi mark the output is: Mark: 1 hey: 1 hi: 2 mark: 1 python # The words parameter is a list of strings.def build_dictionary(words): # The frequencies dictionary will be built with your code below. # Each key is a word string and the corresponding value is an integer # indicating that word's frequency. ''' Type your…Implement the build_dictionary() function to build a word frequency dictionary from a list of words. Ex: If the words list is: ["hey", "hi", "Mark", "hi", "mark"] the dictionary returned from calling build_dictionary(words) is: {'hey': 1, 'hi': 2, 'Mark': 1, 'mark': 1} Ex: If the words list is: ["zyBooks", "now", "zyBooks", "later", "zyBooks", "forever"] the dictionary returned from calling build_dictionary(words) is: {'zyBooks': 3, 'now': 1, 'later': 1, 'forever': 1} The main code builds the word list from an input string, calls build_dictionary() to build the dictionary, and displays the dictionary sorted by key value. Ex: If the input is: hey hi Mark hi mark the output is: Mark: 1 hey: 1 hi: 2 mark: 1 this is the code im supposed to use: # The words parameter is a list of strings.def build_dictionary(words): # The frequencies dictionary will be built with your code below. # Each key is a word string and the corresponding value is an integer # indicating that word's…
- Implement the build_dictionary() function to build a word frequency dictionary from a list of words. Ex: If the words list is: ["hey", "hi", "Mark", "hi", "mark"] the dictionary returned from calling build_dictionary(words) is: {'hey': 1, 'hi': 2, 'Mark': 1, 'mark': 1} Ex: If the words list is: ["zyBooks", "now", "zyBooks", "later", "zyBooks", "forever"] the dictionary returned from calling build_dictionary(words) is: {'zyBooks': 3, 'now': 1, 'later': 1, 'forever': 1} The main code builds the word list from an input string, calls build_dictionary() to build the dictionary, and displays the dictionary sorted by key value. Ex: If the input is: hey hi Mark hi mark the output is: Mark: 1 hey: 1 hi: 2 mark: 1 python please-I submitted some previous code that gave me a space between the Name/work and : that is not supposed to be thereWrite a function that takes a dictionary representing points in 3D space and an associated color for each point, and returns the centroid of the set of points in each color as another dictionary. The keys in the input dictionary are tuples representing the coordinates of points in 3D space and the values are strings representing colors. The keys in the resulting dictionary are colors, and the values are tuples representing the centroids. For example, the following is a valid input dictionary: dict1 = {(1,1,1):"red", (2,1,-1):"green", (0,-1,1):"red", (0,0,-2):"blue"} In this case, there are 2 red points, and their centroid is at ( (1+0)/2, (1-1)/2, (1+1)/2 ) = (0.5, 0, 1) Considering that in this example there is only one green and one blue point, they are representing the respective color's centroid. Hence, your function should return the following dictionary: {"red":(0.5,0.0,1.0), "green":(2.0,1.0,-1.0), "blue":(0.0,0.0,-2.0)} Note that, there is no restriction on the number of…Write a function that takes a dictionary representing points in 3D space and an associated color for each point, and returns the centroid of the set of points in each color as another dictionary. The keys in the input dictionary are tuples representing the coordinates of points in 3D space and the values are strings representing colors. The keys in the resulting dictionary are colors, and the values are tuples representing the centroids. For example, the following is a valid input dictionary: dict1 = {(1,1,1):"red", (2,1,-1):"green", (0,-1,1):"red", (0,0,-2):"blue"} In this case, there are 2 red points, and their centroid is at ( (1+0)/2, (1-1)/2, (1+1)/2 ) = (0.5, 0, 1) Considering that in this example there is only one green and one blue point, they are representing the respective color's centroid. Hence, your function should return the following dictionary: {"red":(0.5,0.0,1.0), "green":(2.0,1.0,-1.0), "blue":(0.0,0.0,-2.0)} Note that, there is no restriction on the number of…