Write a nested loop to print the following for any n x n image of odd dimensions: Example Output (n==5): XXXXO XXX0X XXOX0 XOX00 OX000 Example Output (n==3): XX0 XOX OX O

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“Days Into Year (C++)” By using my code (photo is attached), implement a Days Into Year function. It MUST BE of this form: int daysIntoYear ( int year, int month, int day ) ; In terms of "Days Into Year," how many days are we into the year based on a given date? For example, January 1 is 1 day into the year.   Please have the code display 12 test cases with the result from the function, and the number of days into the year from some other source.   So you can hand calculate the days into the year or use an internet web page.   The typical output might look like this: (Please make the format better but be sure to automatically calculate agree/disagree column) You must include a leap year function that returns a bool and takes as a parameter the year. This function must be used in your code.      Year    Month    day    Days Into Year     Value expected       Agree/Disagree 2020     1           1               1                     1                            agree 2020     1…

Python (this is not graded this is practice work that is not graded) write and test a function which takes two dates (month, day) list arguments.When the function is called with the two arguments, it returns the number of days betweenthose two dates. Print the returned value. It is assumed that the first date occurs first. Forinstance, if the users calls the function with FUNCTION([12, 10], [12, 20]) as arguments, thereturned value is 10 days. However, if FUNCTION([12, 20], [12, 10]) is called, the returnedvalue is -10 days.Assume February has 28 days.Test data: [10, 30], [5, 20] [1, 30], [5, 25] [5, 25], [1, 30] [1, 1], [12, 31]