Write a pseudocode for the synchronous version of broadcast algorithm and work out its time and message complexities.

add x5, x5, x8Every binary digit must be either 0 or 1 or X. If it appears in multiple bits, then you must input multiple bits, e.g.: 0011xx11Control Signal: Value

In this problem we will work through a round of DES. For notational simplicity, assume it is the first round. Please enter all answers as strings of 0's and 1's. The input is the 64 bit block 0000000000000010000000000000001000000100000001000100000000000000 Suppose that the subkey for the current round is this 48 bit number: 000000000000000001000000000000000000000000000000 What does the 64 bit state look like after the IP transformation is applied to the input? 00000000000110000100000000000000 Now find Lo and Ro, the left and right halves of the state. Lo 01000000010000000000000000010000 = Ro=00000000000000100000000000000000 What is the result of applying the expansion box to R₁? E(Ro) = 00000000000000100000000000000000 What is the result of XORing the subkey with E(Ro)? k₁ E(Ro) = 00000000000000100000000000000000 We now apply the S-box transformation. S(k₁ E(Ro)) = 11011000110110001101111110111100 Finally we apply the permutation box to complete the function f. f(Ro) = P(S(k₁ + E(Ro)))…

Next time you snap a picture,  you realize you are capturing millions of pixels into a buffer.  The buffer data is read and converted into JPEG in real time.  Each pixel in that buffer is  an unsigned int  (four bytes ): Alpha, Blue, Green, and Red.  Let us ignore alpha for now.  As you know, a unsigned byte can have a value 0 to 255.  In remote sensing jargons,  it is called blue channel, green channel, and red channel.  Each channel  provides valuable information such as, say farm lands, forest fire, drought, landscape,  diseases ,    If a pixel has a value (say in hex) = 0x00a1b1c1 ,  then 0xc1 is the red pixel, 0xb1 is the green pixel, 0xa1 is the blue and 00 is the alpha. #define RED 1 #define GREEN 2 #define BLUE 3   then, develop a function   void  calculateSum ( unsigned int *ptr , int count ,  unsigned char channel ,  unsigned int *sum,  float *average ) {  *sum = 0;     if (channel == RED )        calculate sum and average for red channel     else     if (channel == GREEN )…