Write the balanced neutralization reaction that occurs between H2SO4H2SO4 and KOHKOH in aqueous solution. Phases are optional. Suppose 0.650 L0.650 L of 0.440 M H2SO40.440 M H2SO4 is mixed with 0.600 L0.600 L of 0.240 M KOH0.240 M KOH. What concentration of sulfuric acid remains after neutralization?

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A: P2O5 = 2 (NH4)3PO4 • 12Mo O3 = 24 PbMoO4   Moles of PbMoO4 are, Moles = mass ÷ molar mass Moles =…

Q: 16.792 g of Ba(OH)2 (171.342 g.mol-1) is weighed out and carefully dissolved to make a 500.00cm3…

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Q: Write the balanced neutralization reaction that occurs between H2SO4 and KOH in aqueous solution.…

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Q: Aluminum in an ore sample is determined by dissolving it and then precipitating with base as Al(OH)3…

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A: The balanced reaction taking place is given as, Given : Concentration of KMnO4 = 0.03190 M Volume…

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Q: Ammonia (NH3, MM 17.031 g/mol) and hypobromite (OBr−) react according to the following chemical…

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Q: An iron ore was analyzed by dissolving a 2.9912-g sample in concentrated HCI. The resulting solution…

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Q: Write the balanced neutralization reaction that occurs between H2SO4 and KOH in aqueous solution.…

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Q: a) What mass of strontium nitrate (Sr(NO3)2) would be required to prepare 2.000 L of a 0.0180 M…

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Q: The reaction of WCl6 with Al at ~400 °C gives black crystals of a compound containing only tungsten…

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Q: Treatment of a 0.2500-g sample of impure potassium chloride with an excess of AgNO3 resulted in the…

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Q: 16.792 g of Ba(OH)2 (171.342 g.mol-1) is weighed out and carefully dissolved to make a 500.00cm3…

A:

Q: Suppose 0.750 L0.750 L of 0.440 M H2SO40.440 M H2SO4 is mixed with 0.700 L0.700 L of 0.300 M…

A: The balanced neutralization reaction between sulfuric acid and potassium hydroxide is given by

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".