   # The thallium (present as Tl 2 SO 4 ) in a 9.486-g pesticide sample was precipitated as thallium(I) iodide. Calculate the mass percent of Tl 2 SO 4 in the sample if 0.1824 g ofTlI was recovered. ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 6, Problem 99AE
Textbook Problem
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## The thallium (present as Tl2SO4) in a 9.486-g pesticide sample was precipitated as thallium(I) iodide. Calculate the mass percent of Tl2SO4 in the sample if 0.1824 g ofTlI was recovered.

Interpretation Introduction

Interpretation:

To calculate the mass percent of in the sample if 0.1824 g of TlI was recovered. The thallium present as ( Tl2SO4 ) in a 9.486-g pesticide sample was precipitated as thallium ( I ) iodide

Concept Introduction:

When two soluble salts are mixed together, an insoluble salt formation could occur called as precipitate and the reactions are called precipitation reactions.

Formula:

Noofmoles=weight(g)molecularweight(g)Massofthecompound=Numberofmoles×Molecularmass

### Explanation of Solution

Explanation

Mass percent of thallium present as thallium sulphate= 9.486 gram

Mass of thallium iodide= 0.1824gram

Thallium iodide was precipitated from the sample of thallium sulphate

The chemical equation can be given as,

Tl++I-TlI(s)

The molar mass of thallium iodide and thallium sulphate has to be calculated in order to find the average mass of thallium sulphate

Molar mass of thallium sulphate was found to be= 504.7 gram

Molar mass of thallium iodide was found to be= 331.2gram

Therefore, the average mass of thallium sulphate can be found to be,

Average mass = 0.1824gofTlI×1molofTlI331.2 gofTlI×1molofTl1molofTl×1molofTl2SO42 molofTl×504.7gramofTl2SO41molofTl2SO4

= 0

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