Write the method public int sumRow(int[][] matrix, int row) that sums row row in the 2D array called matrix.
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- given an array of integer values , return true if 6 appears as either the first or last element in the array. firstLast6([1,2,36]) true firstLast([6,1,2,3]) true firstLast([13,6,1,2,3]) falseComplete the method int getMaxRow(int[][] a) to return the index of the "row" in the two-dimensional array a with the highest row sum. (The row sum is the sum of all the elements in a particular row.)Write a method that returns the sum of all the elementsin a specified row in a matrix using the following header:public static double sumRow(double[][] m, int rowIndex)Point
- By using JavaScript find the sum of all the elements of a given array (before removing and after removing) and removes the last element from an array? [2, 3, 4, 6, 30, 23] Answer it as soon as possible to get the upvot.Write the method sum2D() which accepts a two dimensional integer array and returns the sum of all the elements of the array.Write a program that deletes the first element in an array which matches a search key. Advance thanks <3
- Write program java Create 2D array 4 *5. Ask the user to enter the number inside the array. Print the numbers organized by rows. Calculate the average for each row. Print the least average. Finally, create a method that receives a 2D array to print its elements reverse starting from the last element.Write a program to ask the user for the number of arrays he wants to maintain and then populate eacharray by taking elements from the user. Merge all these arrays in another array and finally remove duplicateelements from the merged array.# the method take another circular array and returns a linear array containing the common elements between the two circular arrays. def intersection(self, c2): # To Do print("==========Test 10==========") lin_arr9 = [10, 20, 30, 40, 50, None, None, None] c10 = CircularArray(lin_arr9, 5, 5) c10.printFullLinear() # This should print: 40, 50, None, None, None, 10, 20, 30 lin_arr10 = [5, 40, 15, 25, 10, 20, 5, None, None, None, None, None] c11 = CircularArray(lin_arr10, 8, 7) c11.printFullLinear() # This should print: 10, 20, 5, None, None, None, None, None, 5, 40, 15, 25 output = c10.intersection(c11) print(output) # This should print: [10, 20, 40]
- What will be the problem with the following algorithm for finding an item in an unsorted array? How can you solve it? int location = 0; bool moreToSearch = (location > length); found = false; while (moreToSearch && !found) { if(item == info[location]) { item = info[location]; } else { location++; moreToSearch = (location > length); } }In the "Common Array Algorithms" section, you learned how to find the position of an element in an array. Suppose you want to find the position of the second match. You could remove the first match and start over, but that would be wasteful. Instead, adapt the algorithm from that section so that it starts the search at a given position, not zero. Complete the following code.Create an array of 3,4,5,2,6,3,7,3,8,9 elements and find the most occurring element in the array i.e., 3.