You are given as following : 20 µl pure LDH on ice, 2.0ml of 6mM NAD+, 2.0ml of 150mM lactate, and 0.14M CAPS buffer. LDH reaction cocktail has final concentration of 1mM NAD+ and 25mM lactate in 0.14M CAPS buffer. LDH activityis measured by mixing 10 µl of LDH sample and 990 µl LDH reaction cocktail before getting ∆A340/min reading on spectrometer. (a). Describe in detail how you would prepare for your LDH reaction cocktail including how to make dilutions.
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You are given as following : 20 µl pure LDH on ice, 2.0ml of 6mM NAD+, 2.0ml of 150mM lactate, and 0.14M CAPS buffer.
LDH reaction cocktail has final concentration of 1mM NAD+ and 25mM lactate in 0.14M CAPS buffer. LDH activityis measured by mixing 10 µl of LDH sample and 990 µl LDH reaction cocktail before getting ∆A340/min reading on spectrometer.
(a). Describe in detail how you would prepare for your LDH reaction cocktail including how to make dilutions.
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- You have been provided with stock solutions of: stock A: 0.06 M sodium pyrophosphate buffer pH 8.5 stock B: 3 M ethanol stock C: 0.015 M NAD+ stock D: milli Q water Determine the volume you will need of each solution to prepare a buffer of with a final volume of 60 mL containing 10 mM sodium pyrophosphate pH 8.5, 100 mM ethanol, 1 mM NAD+. i.e. volume of stock A = _________mL volume of stock B = _________mL volume of stock C = _________mL volume of stock D = _________mL Show your calculations to arrive at your answers.The equation of the double reciprocal plot is y = 0.5294 x + 1.4960. What is the value of vmax (in M/s)? The substrate concentration is given in units of molarity (M) and reaction velocity has units of molarity per second (M/s). (Report to three significant figures)Consider the following reaction at 25°C with the ΔG°’ = +1800 J/mol for the forward reaction.The molar concentrations at the beginning of the reaction were [A] = 19 mM and [B] = 10 mM.After 1 hour, the concentrations were [A] = 16 mM and [B] = 13 mM. Calculate the ΔG of the reaction at the 1 hour timepoint. Please round to 1 decimal point.Gas constant = 8.315 J/mol K
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- Inspired by the sacrifices done by the protector Naevis, Winter was determined to continue Naevis’ experiments with the compounds discovered from Kwangya. Winter searched for all the surviving data from the aftermath of the battle against the Black Mamba and found the following graphs and values. The general reaction for the formation of compound Ae is as follows: Nvs + We + Luv + You → Ae (See picture) Table 1. Reaction rates of various Ae formation runs at 30 oC. Run Concentration of each component in Solution Initial rate, M/s [Nvs], M [We], M [Luv], M [You], M 1 0.053 0.082 0.092 0.046 8.44 x 10-10 2 0.029 0.096 0.092 0.034 1.87 x 10-10 3 0.053 0.074 0.092 0.034 6.24 x 10-10 She also found a numerical value for k = 7.1 x 10-5 but was not able to find its unit. Help her find the following: Order of the reaction with respect to Luv (round off to the nearest whole number) Unit of the rate constant Rate Law of…Convert the experimental glucose concentration from mM (millimolar) to g/100 mL. 1/100 Dilution factor, Assume 1L of Solution. Show ALL Steps 2.340 mMcalculate the reaction velocity at saturating substrate concentrations. Your numerical answer is assumed to be in units of M sec-1. [S] = 100 mM k1 = 10 sec-1 k2 = 3000 sec-1 k-1 = 20 sec-1 [E]T = 1 \muμM