You will use three corn syrup solutions of 10.0, 20.0 and 30.0% by mass in your Virtual Lab activity. Calculate the approximate molarity of each of the three corn syrup solutions from their mass %. Assume that the density of the solutions is 1.00g/ml. (Pure corn syrup is 14.0 g/ml so this a close approximation). Also assume that the ingredients in corn syrup are glucose C6H12O6 (342 g/mole) and water, we will ignore any other solutes for this problem.

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Chapter12: Solutions
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Problem 12.96QP: A sample of aluminum sulfate 18-hydrate, Al2(SO4)3. 18H2O, containing 125.0 mg is dissolved in 1.000...
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You will use three corn syrup solutions of 10.0, 20.0 and 30.0% by mass in your Virtual Lab activity. Calculate the approximate molarity of each of the three corn syrup solutions from their mass %. Assume that the density of the solutions is 1.00g/ml. (Pure corn syrup is 14.0 g/ml so this a close approximation). Also assume that the ingredients in corn syrup are glucose C6H12O6 (342 g/mole) and water, we will ignore any other solutes for this problem.
You will use three corn syrup solutions of 10.0, 20.0 and 30.0% by mass in your
Virtual Lab activity. Calculate the approximate molarity of each of the three corn
syrup solutions from their mass %. Assume that the density of the solutions is
1.00g/ml. (Pure corn syrup is 14.0 g/ml so this a close approximation). Also assume
that the ingredients in corn syrup are glucose C6H12O6 (342 g/mole) and water, we
will ignore any other solutes for this problem.
Transcribed Image Text:You will use three corn syrup solutions of 10.0, 20.0 and 30.0% by mass in your Virtual Lab activity. Calculate the approximate molarity of each of the three corn syrup solutions from their mass %. Assume that the density of the solutions is 1.00g/ml. (Pure corn syrup is 14.0 g/ml so this a close approximation). Also assume that the ingredients in corn syrup are glucose C6H12O6 (342 g/mole) and water, we will ignore any other solutes for this problem.
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