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All Textbook Solutions for Introduction to Business Statistics

9.12E9.13E9.14E9.15E9.16E9.17E9.18E9.19E9.20E9.21E9.22E9.23E9.24E9.25E9.26E9.27E9.28E9.29E9.30E9.31E9.32E9.33E9.34E9.35E9.36E9.37E9.38E9.39E9.40E9.41E9.42E9.43EAn airline has surveyed a simple random sample of air travelers to find out whether they would be interested in paying a higher fare in order to have access to e-mail during their flight. Of the 400 travelers surveyed, 80 said e-mail access would be worth a slight extra cost. Construct a 95% confidence interval for the population proportion of air travelers who are in favor of the airline’s e-mail idea.9.45E9.46E9.47E9.48E9.49E9.50E9.51E9.52E9.53E9.54EEstelle McCarthy, a candidate for state office in New Jersey, has been advised that she must get at least 65% of the union vote in her state. A recent political poll of likely voters included 800 union-member respondents, and 60% of them said they intended to vote for Ms. McCarthy. Based on the survey, construct and interpret the 95% confidence interval for the population proportion of likely-voter union members who intend to vote for Ms. McCarthy. Is the 65% level of support within the confidence interval?Given your answer to the preceding question, commenton the possibility that Ms. McCarthy might not succeed in obtaining the level of union support she needs.9.56E9.57E9.58E9.59E9.60E9.61E9.62E9.63E9.64E9.65E9.66E9.67E9.68E9.69E9.70E9.71E9.72E9.73E9.74E9.75E9.76E9.77E9.78E9.79E10.90CE10.91CE10.92CE10.93CE10.94CE10.95CE10.96CE10.97CE10.98CE10.99CE10.100CE10.101CE10.102CE10.103CE10.104CE10.105CE10.106CE10.107CE10.108CE10.109CE10.110CE10.111CE10.112CE10.113CE2.1IC2.2IC12.1AE12.2AE12.3AE13.1AE13.2AE13.3AE13.4AE10.1E10.2E10.3EThe president of a company that manufactures central home air conditioning units has told an investigative reporter that at least 85% of its homeowner customers claim to be “completely satisfied” with the overall purchase experience. If the reporter were to subject the president’s statement to statistical scrutiny by questioning a sample of the company’s residential customers, would the test be one-tail or two-tail? What would be the appropriate null and alternative hypotheses?10.5E10.6EFollowing a major earthquake, the city engineer must determine whether the stadium is structurally sound for an upcoming athletic event. If the null hypothesis is “the stadium is structurally sound,” and the alternative hypothesis is “the stadium is not structurally sound,”which type of error (Type I or Type II) would the engineer least like to commit?10.8E10.9E10.10E10.11E10.12E10.13E10.14E10.15E10.16E10.17E10.18E10.19E10.20E10.21E10.22E10.23E10.24E10.25E10.26E10.27E10.28E10.29EIn the past, patrons of a cinema complex have spent an average of $5.00 for popcorn and other snacks, with a standard deviation of $1.80. The amounts of these expenditures have been normally distributed. Following an intensive publicity campaign by a local medical society, the mean expenditure for a sample of 18 patrons is found to be $4.20. In a one-tail test at the 0.05 level of significance, does this recent experience suggest a decline in spending? Determine and interpret the p-value for the test.Following maintenance and calibration, an extrusion machine produces aluminum tubing with a mean outside diameter of 2.500 inches, with a standard deviation of 0.027 inches. As the machine functions over an extended number of work shifts, the standard deviation remains unchanged, but the combination of accumulated deposits and mechanical wear causes the mean diameter to “drift” away from the desired 2.500 inches. For a recent random sample of 34 tubes, the mean diameter was 2.509 inches. At the 0.01 level of significance, does the machine appear to be in need of maintenance and calibration? Determine and interpret the p-value for the test.A manufacturer of electronic kits has found that the mean time required for novices to assemble its new circuit tester is 3 hours, with a standard deviation of 0.20 hours. A consultant has developed a new instructional booklet intended to reduce the time an inexperienced kit builder will need to assemble the device. In a test of the effectiveness of the new booklet, 15 novices require a mean of 2.90 hours to complete the job. Assuming the population of times is normally distributed, and using the 0.05 level of significance, should we conclude that the new booklet is effective? Determine and interpret the p-value for the test. ( DATA SET ) Note: Exercises 10.33 and 10.34 require a computer and statistical software.10.33EA machine that fills shipping containers with driveway filler mix is set to deliver a mean fill weight of 70.0 pounds. The standard deviation of fill weights delivered by the machine is known to be 1.0 pounds. For a recent sample of 35 containers, the fill weights are listed in data file XR10034. Using the mean for this sample, and assuming that the population standard deviation has remained unchanged at 1.0 pounds, examine whether the mean fill weight delivered by the machine might now be something other than 70.0 pounds. Identify and interpret the p-value for the test. Using the 0.05 level of significance, what conclusion will be reached?10.35E10.36E10.37E10.38E10.39E10.40E10.41EThe average age of passenger cars in use in the United States is 9.0 years. For a simple random sample of 34 vehicles observed in the employee parking area of a large manufacturing plant, the average age is 10.4 years, with a standard deviation of 3.1 years. At the 0.01 level of significance, can we conclude that the average age of cars driven to work by the plant’s employees is greater than the national average? Source: polk.com, August 9, 2006.10.43E10.44E10.45E10.46E10.47EDuring 2008, college work-study students earned a mean of $1478. Assume that a sample consisting of 45 of the work-study students at a large university was found to have earned a mean of $1503 during that year, with a standard deviation of $210. Would a one-tail test at the 0.05 level suggest the average earnings of this university’s work-study students were significantly higher than the national mean? Source: Bureau of the Census, StatisticalAbstract of the United States 2009, p. 178.10.49E10.50E10.51EIn response to an inquiry from its national office, the manager of a local bank has stated that her bank’s average service time for a drive-through customer is93 seconds. A student intern working at the bank happens to be taking a statistics course and is curious as to whether the true average might be some value other than 93 seconds. The intern observes a simple random sample of 50 drive-through customers whose average service time is 89.5 seconds, with a standard deviation of 11.3 seconds. From these sample results, and using the 0.05 level of significance, what conclusion would the student reach with regard to the bank manager’s claim?10.53E10.54E10.55E10.56E10.57E10.58E10.59E10.60E10.61E10.62E10.63E10.64E10.65E10.66E10.67E10.68E10.69E10.70E10.71E10.72E10.73E10.74E10.75E10.76E10.77E10.78E10.79E10.80E10.81E10.82E10.83E10.84E10.85E10.86E10.87E10.88E10.89E11.75CE11.76CE11.77CE11.78CE11.79CE11.80CE11.81CE11.82CE11.83CE11.84CE11.85CE11.86CE11.87CE11.88CE11.89CE11.90CE11.91CE11.92CE11.93CE11.94CE11.95CE11.96CE11.97CE11.98CE11.99CE11.100CE11.101CE1.1IC1.2IC1.3IC2.1IC2.2IC2.3IC2.4IC1BC2BC3BC14.1AE14.2AE14.3AE14.4AE14.5AE14.6AE11.1E11.2EUsing independent random samples, a researcher is comparing the number of hours of television viewed last week for high school seniors versus sophomores. The results are shown here. Assuming normal populationswith equal standard deviations, does it appear that the average number of television hours per week could be equal for these two populations? What is the most accurate statement that could be made about the p-value for the test? Seniors: x1=3.9hourss1=1.2hoursn1=32 Sophomores: x2=3.5hourss2=1.4hoursn2=3011.4E11.5E11.6E11.7E11.8E11.9E11.10E11.11E11.12E11.13E11.14E11.15E11.16E11.17E11.18E11.19E11.20E11.21EA tire company is considering switching to a new type of adhesive designed to improve tire reliability in high-temperature and overload conditions. In laboratory “torture” tests with temperatures and loads 90% higher than the maximum normally encountered in the field, 15 tires constructed with the new adhesive run an average of 65 miles before failure, with a standard deviation of 14 miles. For 18 tires constructed with the conventional adhesive, the mean mileage before failure was 53 miles, with a standard deviation of 22 miles. Assuming normal populations and using the 0.05 level of significance, can we conclude that the new adhesive is superior to the old under such test conditions? What is the most accurate statement that could be made about the p-value for this test?11.23E11.24E11.25E11.26E11.27E11.28E11.29E11.30E11.31E11.32E11.33E11.34E11.35E11.36E11.37E11.38E11.39E11.40E11.41E11.42E11.43E11.44E11.45E11.46E11.47E11.48EThe students in an aerobics class have been weighed both before and after the 5-week class, with the following results: Using the 0.05 level of significance, evaluate the effectiveness of the program. Using the appropriate statistical table, what is the most accurate statement we can make about the p-value for this test?11.50E11.51E11.52E11.53E11.54E11.55E11.56E11.57E11.58E11.59E11.60E11.61E11.62E11.63E11.65E11.66E11.67E11.68E