Chapter 10, Problem 29SGR

To determine

To find: The equation of the circle.

Answer to Problem 29SGR

The equation of the circle is ${\left(x-1\right)}^2+{\left(y-6\right)}^2=9$

Explanation of Solution

Given information:

The given data is $center\left(-1,6\right),r=3$

Calculation:

The given data is.

  $center\left(-1,6\right),r=3$

The standard form of the equation is,

  ${\left(x-h\right)}^2+{\left(y-k\right)}^2=r^2$

The equation of the circle is.

  $\begin{array}{l}{\left(x-1\right)}^2+{\left(y-6\right)}^2=3^2\\ {\left(x-1\right)}^2+{\left(y-6\right)}^2=9\end{array}$