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6th Edition

KASSIMALI + 1 other

Publisher: Cengage,

ISBN: 9781337630931

Chapter 12, Problem 7P

Textbook Problem

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Determine the approximate axial forces, shears, and moments for all the members of the frames shown in Figs. P12.6 through P12.13 by using the portal method.

FIG. P12.7, P12.15

To determine

Find the approximate axial forces, shears, and moments for the all members of the frames using portal method.

**Given information:**

The axial force acting at point *D*

The vertical distance of the member *AD*, *BE*, and *CF*

The horizontal distance of the members *AB* and *BC*

The horizontal distance of the members *DE* and *EF*

**Calculation:**

Insert the internal hinges at the midpoints of all the members of the given frame to obtain the simplified frame for approximate analysis.

Draw the simplified frame as in Figure (1).

For the calculation of column shears in the columns of the frame, pass an imaginary section *aa* through the columns just above the support level.

Draw the free body diagram of the frame portion above section *aa* as in Figure (2).

**Colum shears:**

Consider the shear in the interior column *BE* is twice as much as in the exterior columns *AD* and *CF*.

Determine the column shears at the lower end using equilibrium equations.

Substitute 50 k for

The shear force at the lower end of the columns

Determine the shear force at the interior column.

Substitute –12.5 k for *S*.

Draw the free body diagram of frame with the column shear value at the lower end column as in Figure (3).

**Column moments:**

Consider the aniticlockwise moment is positive and clockwise moment is negative.

Determine the moment at the column member *AD*.

Substitute 12.5 k for *S* and 20 ft for *L*.

The moment at the column *AD* is equal to moment at the column *CF*. Therefore, the moment at the column member *AD* and *CF* is

Determine the moment at the column member *BE*.

Substitute –125 k-ft for

The moment at the internal hinge of the horizontal member *DE* and *EF* has the equal maginitude and opposite direction of the moment at the vertical column member *AD*.

Draw the free body diagram of frame with the column moments for frame portion *ADE* as in Figure (4).

**Girder axial forces, moments, and shears:**

Consider girder *DE*.

Determine the girder end action at the upper left end joint *D* using the relation.

Substitute 50 k for *S*.

Determine the vertical shear at the point *D*.

Take moment about hinge at the horizontal member *DE*.

Substitute

Structural Analysis

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Ch. 12 - 12.1 through 12.5 Draw the approximate shear and...Ch. 12 - 12.1 through 12.5 Draw the approximate shear and...Ch. 12 - 12.1 through 12.5 Draw the approximate shear and...Ch. 12 - 12.1 through 12.5 Draw the approximate shear and...Ch. 12 - 12.1 through 12.5 Draw the approximate shear and...Ch. 12 - Determine the approximate axial forces, shears,...Ch. 12 - Determine the approximate axial forces, shears,...Ch. 12 - Determine the approximate axial forces, shears,...Ch. 12 - Determine the approximate axial forces, shears,...Ch. 12 - Determine the approximate axial forces, shears,...

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