Organic Chemistry - Standalone book
Organic Chemistry - Standalone book
10th Edition
ISBN: 9780073511214
Author: Francis A Carey Dr., Robert M. Giuliano
Publisher: McGraw-Hill Education
bartleby

Concept explainers

bartleby

Videos

Textbook Question
Book Icon
Chapter 14.4, Problem 3P

The 1H NMR signal for bromoform ( CHBr 3 ) appears at 2065

Hz when recorded on a 300 -MHz NMR spectrometer. (a) What is the chemical shift of this proton? (b) If the spectrum was recorded on a 400 -MHz instrument, what would be the chemical shift of the CHBr 3 proton? (c) How many hertz downfield from TMS is the signal when recorded on a 400 -MHz instrument?

Blurred answer
Students have asked these similar questions
The 1H NMR spectrum of CH3OH recorded on a 500 MHz NMR spectrometer consists of two signals, one due to the CH3 protons at 1715 Hz and one due to the OH proton at 1830 Hz, both measured downeld from TMS. (a) Calculate the chemical shift of each absorption. (b) Do the CH3 protons absorb upeld or downeld from the OH proton?
Which of the following compounds of molecular formula C6H1002, shows two singlets in its' H-NMR with areas of 2: 3, where the signal that integrates by 2 has a greater chemical shift?
Which compounds give a 1H NMR spectrum with two signals in a ratio of 2:3?

Chapter 14 Solutions

Organic Chemistry - Standalone book

Ch. 14.7 - Describe the appearance of the 1H NMR spectrum of...Ch. 14.8 - Describe the appearance of the 1H NMR spectrum of...Ch. 14.11 - Prob. 13PCh. 14.11 - Prob. 14PCh. 14.12 - Hydrogen bonding between the oxygen of dimethyl...Ch. 14.14 - Prob. 16PCh. 14.15 - The 13C NMR spectrum of 1-bromo-3-chloropropane...Ch. 14.15 - Consider carbons x, y, and z in p-methylanisole....Ch. 14.15 - Prob. 19PCh. 14.16 - To which of the compounds of Problem 14.16 does...Ch. 14.18 - DEPT spectra for a compound with the formula...Ch. 14.20 - Vibrational frequencies are sensitive to isotopic...Ch. 14.21 - Prob. 23PCh. 14.22 - Prob. 24PCh. 14.23 - Prob. 25PCh. 14.23 - Which one of the C5H8 isomers shown has its max at...Ch. 14.24 - Knowing what to look for with respect to isotopic...Ch. 14.24 - The base peak appears at m/z105 for one of the...Ch. 14.24 - Mass spectra of 1-bromo-4-propylbenzene and...Ch. 14.25 - Prob. 30PCh. 14 - Each of the following compounds is characterized...Ch. 14 - Deduce the structure of each of the following...Ch. 14 - From among the isomeric compounds of molecular...Ch. 14 - The H1NMR spectrum of fluorene has signals at 3.8...Ch. 14 - Prob. 35PCh. 14 - H1NMR spectra of four isomeric alcohols with...Ch. 14 - Prob. 37PCh. 14 - We noted in Section 14.13 that an NMR spectrum is...Ch. 14 - Identify each of the C4H10O isomers on the basis...Ch. 14 - A compound (C3H7ClO2) exhibited three peaks in its...Ch. 14 - Label nonequivalent carbons in the following...Ch. 14 - Compounds A and B are isomers of molecular formula...Ch. 14 - C13 NMR spectra for four isomeric alkyl bromides...Ch. 14 - Prob. 44PCh. 14 - Prob. 45PCh. 14 - Identify the C3H5Br isomers on the basis of the...Ch. 14 - Prob. 47PCh. 14 - A compound (C8H10O) has the IR and H1NMR spectra...Ch. 14 - Deduce the structure of a compound having the...Ch. 14 - Figure 14.53 presents IR, H1NMR, C13NMR and mass...Ch. 14 - H1NMR, C13NMR, IR, and mass spectra are shown for...Ch. 14 - 1H NMR and IR spectra for a compound with the...Ch. 14 - FriedelCraftsalkylation of benzene with...Ch. 14 - Prob. 54DSPCh. 14 - Prob. 55DSPCh. 14 - Prob. 56DSPCh. 14 - Prob. 57DSPCh. 14 - Prob. 58DSP
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
  • Text book image
    Organic Chemistry
    Chemistry
    ISBN:9781305080485
    Author:John E. McMurry
    Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305080485
Author:John E. McMurry
Publisher:Cengage Learning
Mass Spectrometry; Author: Professor Dave Explains;https://www.youtube.com/watch?v=hSirWciIvSg;License: Standard YouTube License, CC-BY