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Fundamentals of Chemical Engineeri...

1st Edition
Kevin D. Dahm + 1 other
Publisher: Cengage Learning
ISBN: 9781111580704
BuyFind

Fundamentals of Chemical Engineeri...

1st Edition
Kevin D. Dahm + 1 other
Publisher: Cengage Learning
ISBN: 9781111580704

Solutions

Chapter
Section
Chapter 1.7, Problem 17P
Textbook Problem
502 views

A gas at T = 300 K and P = 1 bar is contained in a rigid, rectangular vessel that is 2 meters long, 1 meter wide, and 1 meter deep. How much force does the gas exert on the walls of the container?

Expert Solution
Interpretation Introduction

Interpretation:

The force exerted by the gas on the container walls has to be determined.

Concept Introduction:

Area (A) of the rectangular vessel:

A=(2wh)+(2wl)+(2hl)

Here, width of rectangular vessel is w, depth is h, and length is l.

The force (F) exerted by the gas on the container walls.

F=PA

Here, pressure is P.

Explanation of Solution

Write the expression for the area (A) of the rectangular vessel.

A=(2wh)+(2wl)+(2hl)        (1)

Here, width of rectangular vessel is w, depth is h, and length is l.

Calculate the force (F) exerted by the gas on the container walls.

F=PA        (2)

Here, pressure is P.

Given information:

Temperature of gas is T=300 K.

Pressure of gas is P=1 bar.

Dimension of rectangular vessel is,

Length =2 meter

Width =1 meter

Height =1 meter

Substitute 1m for w, 1m for h, and 2m for l in equation (1)

A=[2(1m)(1m)]+[2(1m)(2m)]+[2(1m)(2m)]=2m2+4m2+4m</

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