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Chemical Engineering Fundamentals of Chemical Engineering Thermodynamics (MindTap Course List)1st Edition

A car weighs 3000 lb m and is travelling 60 mph when it has to make an emergency stop. The car comes to a stop 5 seconds after the brakes are applied. A. Assuming the rate of deceleration is constant, what force is required? B. Assuming the rate of deceleration is constant, how much distance is covered before the car comes to a stop?

Fundamentals of Chemical Engineeri...

1st Edition

Kevin D. Dahm + 1 other

Publisher: Cengage Learning

ISBN: 9781111580704

Solutions

Chapter

Section

Fundamentals of Chemical Engineeri...

1st Edition

Kevin D. Dahm + 1 other

Publisher: Cengage Learning

ISBN: 9781111580704

Chapter 1.7, Problem 18P

Textbook Problem

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A car weighs 3000 lb_m and is travelling 60 mph when it has to make an emergency stop. The car comes to a stop 5 seconds after the brakes are applied.

A. Assuming the rate of deceleration is constant, what force is required?

B. Assuming the rate of deceleration is constant, how much distance is covered before the car comes to a stop?

A)

Interpretation Introduction

Interpretation:

The amount of force required to stop the car when the deceleration is constant.

Concept Introduction:

The acceleration of the car.

a=vf−vit

Here, final velocity is vf, initial velocity is vi, and time is t.

The required force to stop the car:

F=M×a

Here, mass is M and acceleration is a.

Explanation of Solution

Given information:

Weight of the car =3000 lbm

Speed of the car =60 mph

Time taken to stop the car =5 s

Calculate the acceleration of the car.

a=vf−vit (1)

Here, final velocity is vf, initial velocity is vi, and time is t.

Substitute 0 for vi, 60 mph for vf, and 5 s for t in equation (1).

a=60 mph−05 s=60 mph×(1.466 fts)5 s=17.592 ft/s2

Calculate the force required to stop the car

B)

Interpretation Introduction

Interpretation:

The distance covered by the car before it comes to stop.

Concept Introduction:

The distance covered before the car comes to a stop.

df=a×t22+vf×t+di

Here, initial distance is di, final distance is df, and initial velocity is vi.

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Chapter 1 Solutions

Fundamentals of Chemical Engineering Thermodynamics (MindTap Course List)

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