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ChemistryChemistry: An Atoms First Approach2nd Edition
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Provide a reasonable estimate for the number of atoms in a 150-lb adult human. Use the information given in Table 19-2.

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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

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BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 19, Problem 81AE
Textbook Problem
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Provide a reasonable estimate for the number of atoms in a 150-lb adult human. Use the information given in Table 19-2.

Interpretation Introduction

Interpretation: The number of atoms in 150 lb of adult human is to be estimated using Table 19-2 .

Concept introduction: Number of atoms in a human body is equal to the sum of individual atom of each element present in the human body.

To determine: The number of atoms in 150 lb of adult human.

Explanation of Solution

Mass of each atom is,

  • Mass of oxygen atom is 44226 g_ .
  • Mass of carbon atom is 12247.2 g_ .
  • Mass of hydrogen atom is 6804 g_ .
  • Mass of nitrogen atom is 2041.2 g_ .

Given

Mass of adult human is 150 lb .

Refer to Table 19-2 .

The mass percent of major elements in a human body is,

Element Mass percent (%)
Oxygen (O) 65.0
Carbon (C) 18.0
Hydrogen (H) 10.0
Nitrogen (N) 3.0

The conversion of pound (lb) into gram (g) is done as,

1 lb=453.6 g

Hence, the conversion of 150 lb into gram is,

150 lb=(150 ×453.6 ) g=68040 g

The mass of each element is calculated by multiplying the mass percent with overall mass of human body. Hence, the mass of each element is,

Mass of atoms=Mass percent of atom×Overall mass of human body (1)

Substitute the values of mass percent of oxygen and overall mass of human body in the above equation.

Mass of O atoms=Mass percent of O atom×Overall mass of human body=65.0100×68040=44226 g_

Substitute the values of mass percent of carbon and overall mass of human body in equation (1).

Mass of C atoms=Mass percent of C atom×Overall mass of human body=18.0100×68040=12247.2 g_

Substitute the values of mass percent of hydrogen and overall mass of human body in equation (1).

Mass of H atoms=Mass percent of H atom×Overall mass of human body=10.0100×68040=6804 g_

Substitute the values of mass percent of nitrogen and overall mass of human body in equation (1).

Mass of N atoms=Mass percent of N atom×Overall mass of human body=3

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