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General Chemistry - Standalone boo...

11th Edition
Steven D. Gammon + 7 others
Publisher: Cengage Learning
ISBN: 9781305580343

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BuyFindarrow_forward

General Chemistry - Standalone boo...

11th Edition
Steven D. Gammon + 7 others
Publisher: Cengage Learning
ISBN: 9781305580343
Chapter 22, Problem 22.36QP
Textbook Problem
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For the complexes shown here, which would have the d electron distribution shown in the diagram below: [MF6]3−, [M(CN)6]3−, [MF6]4−, [M(CN)6]4−? Note that the neutral metal atom. M, in each complex is the same and has the ground state electron configuration [Ar]4s23d6.

Chapter 22, Problem 22.36QP, For the complexes shown here, which would have the d electron distribution shown in the diagram

Interpretation Introduction

Interpretation:

Of the complexes – [MF6]3,[M(CN)6]3,[MF6]4,[M(CN)6]4 the complex in which the d-electrons are distributed as given in the problem has to be identified.

Concept Introduction:

The term Crystal field splitting refers to segregation of d-orbitals in to higher energy orbitals and lower energy orbitals when ligands approaches metal ion to co-ordinate.  Crystal field splitting is said to be larger when the energy gap between higher energy d-orbitals and lower energy d-orbitals is larger.  Crystal field splitting is said to be smaller when the energy gap between higher energy d-orbitals and lower energy d-orbitals is smaller.

Spectrochemical series refers to the arrangement of ligands with respect to crystal field splitting they cause in the d-orbitals of a metal ion.  The ligand that causes larger splitting pattern is referred to as stronger ligand.

The ligands are arranged in increasing order of crystal field splitting they produce.

I<Br<S2<SCN<Cl<NO3<N3<F<OH<C2O42<H2O<NCS<CH3CN<py<NH3<en<bipy<phen<NO2<PPh3<CN<CO

Pairing energy refers to the energy required to pair the electrons - that is energy required to make two electrons to be paired in same orbital with opposite spins.

If the pairing energy of a complex is high it means the electrons are difficult to be paired and so the complex will be high spin complex with unpaired electrons.  If the pairing energy of a complex is low it means the electrons are readily paired and so the complex will be low spin complex with paired electrons.

When ligands approach the metal ion the degeneracy in d-orbitals of the metal ion is destroyed and they split into two different energy levels. In case of tetrahedral complex, the dx2y2and dz2 orbitals occupy lower energy level and the dxy,dxz,dyz orbitals occupy higher energy level.  The energy gap between these two set of orbitals is termed as crystal field splitting energy.

Explanation of Solution

There are six d-electrons given in the diagram representing the distribution of d-electrons. Given that central metal atom has configuration [Ar]3d6. It implies the oxidation state of the metal atom is +2.   from the given complexes, the complex with metal ion of oxidation state of +2 is [MF6]4and[M(CN)6]4

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Chapter 22 Solutions

General Chemistry - Standalone book (MindTap Course List)
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Ch. 22 - What characteristics of the transition elements...Ch. 22 - According to the building-up principle, what is...Ch. 22 - The highest melting point for metals in the fifth...Ch. 22 - Iron, cobalt, and nickel are similar in properties...Ch. 22 - Palladium and platinum are very similar to one...Ch. 22 - Write balanced equations for the reactions of Cr...Ch. 22 - Write balanced equations for the reactions of...Ch. 22 - Describe the structure of copper(II) sulfate...Ch. 22 - Silver(I) ion in basic solution is reduced by...Ch. 22 - What evidence did Werner obtain to show that the...Ch. 22 - Define the terms complex ion, ligand, and...Ch. 22 - Define the term bidentate ligand. 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